Class 12th

The compound(s) that is (are) removed as slag during the extraction of copper is:

(A) CaO

(B) FeO

(C) Al₂O_{3 &n}

...more

0 Follower 2 Views

Contributor-Level 10

$F e O + \underset{(A c i d i c f l u x)}{S i O_{2}} \to \underset{(S l a g)}{F e S i O_{3}}$

0 0

New answer posted

8 months ago

The IUPAC nomenclature of an element with electronic configuration [Rn] 5f¹⁴6d¹7s² is:

0 Follower 1 View

Contributor-Level 10

IUPAC nomenclature of element with atomic no. 103 is uniltrium.

0 0

New answer posted

8 months ago

Class 12th Physics

The figure gives experimentally measured $B$ vs $H$ variation in a ferromagnetic material. The retentivity, co-ercivity and saturation, respectively, of the material are

0 Follower 10 Views

Contributor-Level 10

$x =$ retentivity

$y =$ coercivity

$z =$ saturation magnetization

0 0

New answer posted

8 months ago

Match the List-I with List-II

List-I	List-II
(A) N₂(g) + 3H₂(g) -> 2NH₃(g)	(I) Cu
(B) CO(g) + 3H₂(g) -> CH₄(g) + H₂O(g)	(II) Cu/ZnO – Cr₂O₃
(C) CO(g) + H₂(g) -> HCOH(g)	(III) Fe_xO_y + K₂O + Al₂O₃
(D) CO(g) + 2H₂(g) -> CH₃OH(g)	(IV) Ni

Choose the correct answer from the options given below:

0 Follower 2 Views

Contributor-Level 10

Uses of catalyst is very specific for a particular reaction.

0 0

New answer posted

8 months ago

Class 12th Wave Optics

In a Young's double slit experiment, the separation between the slits is $0.15 m m$ . In the experiment, a source of light of wavelength $589 n m$ is used and the interference pattern is observed on a screen kept $1.5 m$ away. The separation between the successive bright fringes on the screen is:

0 Follower 6 Views

Contributor-Level 10

$\frac{Energy}{Volume} = \frac{{M L}^{2} T^{- 2}}{L^{3}} = ({M L}^{- 1} T^{- 2})$

The distance between two successive bright fringes is fringe width $(β)$ .

$β = \frac{λ D}{d} = \frac{589 * 10^{- 9} * 1.5}{0.15 * 10^{- 3}} = 5.9 m m$

0 0

New answer posted

8 months ago

Class 12th Solutions

The depression in freezing point observed for a formic acid solution of concentration 0.5 mL L-1 is $0.0405 ° C .$ Density of formic acid is 1.05 g mL-1. The Van't Hoff factor of the formic acid solution is nearly: (Given for water $K_{f} = 1.86 k k g m o l^{- 1}$ $_{}^{}$ )

0 Follower 4 Views

Contributor-Level 10

Let we take of solution

Mass of solute = Volume * Density

= 0.5 $m l * 1.05 g m / m l$

= 0.525 gram

Mass of solution = 1 kg. [considering very dilute solution]

Mass of solvent = 1000 – 0.525 = 999.475 gram

$\Rightarrow i = 1.9$

0 0

New answer posted

8 months ago

Match List I with List II:

List I (molecule)		List II (hybridization; shape)
A.	XeO₃	I.	sp³d; linear
B.	XeF₂	II.	sp³; pyramidal
C.	XeOF₄	III.	sp³d³; distorted octahedral
D.	XeF₆	IV.	sp³d³; square pyramidal

Choose the correct answer from the options given below

0 Follower 7 Views

Payal Gupta

Contributor-Level 10

$X e O_{3} \Rightarrow s p^{3}, P y r a m i d a l$

XeF₂ sp³d₂, square pyramidal

XeF₆sp³d³, Distorted octahedral

XeOF₄ sp³d², square pyramidal

0 0

New answer posted

8 months ago

SO₂Cl₂ on reaction with excess of water results into acidic mixture

SO₂Cl₂ + H₂O -> H₂SO₄ + 2HCl

16 moles of NaOH is required for the complete neutralization of the resultant acidic mixture. The number of moles of SO₂Cl₂ used is:

0 Follower 9 Views

Contributor-Level 10

$S O_{2} C l_{2} + 2 H_{2} O \to H_{2} S O_{4} + 2 H C l$

Let a moles of SO2Cl2 is taken

Then no. of moles of H2SO4 = a moles

No. of moles of HCl = 2a moles

No. of moles of NaOH required = 2a + 2a = 4a = 16

$\Rightarrow a = 4 m o l e s$

0 0

New answer posted

8 months ago

The total number of Mn = O bonds in Mn₂O₇ is________.

0 Follower 3 Views

Contributor-Level 10

Number of Mn = O bonds = 6

0 0

New answer posted

8 months ago

Given below are two statements.

Statement I: Iron (III) catalyst, acidified K₂Cr₂O₇ and neutral KMnO₄ have the ability to oxidize I^- to I₂ independently.

Statement II: Magnate ion is paramagnetic in nature and involves pp-pp bonding

In the light of the above statements, choose the most appropriate answer from the options given below.

0 Follower 28 Views