Class 12th

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New answer posted

8 months ago

0 Follower 6 Views

P
Payal Gupta

Contributor-Level 10

XeO3 ⇒ Number of lone pair = 1

XeOF4 ⇒ Number of lone pair = 1

XeF6 ⇒ Number of lone pair = 1

New answer posted

8 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

For first order reaction,

ln (PP0)=k.t

K=3.465*104

t1/2=0.6933.465*104=2*105 sec

New answer posted

8 months ago

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Payal Gupta

Contributor-Level 10

For single H- atom, maximum number of spectral lines = (n – 1), n = orbit number of excited electron.

New answer posted

8 months ago

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Payal Gupta

Contributor-Level 10

ein=|d? dt|=|16t9|ein=|16*149|=5volt

l=einR=520A=520*1000mA=250mA

New answer posted

8 months ago

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Payal Gupta

Contributor-Level 10

For refraction of light at lens

1v160=120

1v=1201601v=3160=130

v = 30 cm

If image has to be formed at object itself then light ray should retrace its path. Hence after refraction at lens, it must strikes normally to the mirror

RM = 20 cm Radius of curvature of mirror

Fm = 10 cm focal length of mirror

New answer posted

8 months ago

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Payal Gupta

Contributor-Level 10

CV+q9C+3CV+q3C=0

CV+q9CV+3q=0

q=8CV4=2CV

VAB=CV+q9C=3CV9C=V3=183=6volt

New answer posted

8 months ago

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Payal Gupta

Contributor-Level 10

Here diode-D1 is forced biased and diode-D2 is reversed biased, so

R A B = ( 2 0 / / 2 0 ) + 1 5 = 2 5 Ω

New answer posted

8 months ago

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P
Payal Gupta

Contributor-Level 10

V=KlV2V1=l2l1l236=1.801.20=32l2=54cm

Δl=l2l1=5436=18cm

New answer posted

8 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

According to definition of atomic energy, we can write

E1=E0 (122132)=5E036, andE2=E0 (12212)

E1E2=59xx+4=55+4x=5

New answer posted

8 months ago

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V
Vishal Baghel

Contributor-Level 10

Line of shortest distance will be along b ¯ 1 * b ¯ 2

where  b ¯ 1 = j ^ + k ^ a n d b ¯ 2 = 2 i ^ + 2 j ^ + k ^ b ¯ 1 * b ¯ 2 = | i ^ j ^ k ^ 0 1 1 2 2 1 | = i ^ + 2 j ^ 2 k ^

Angle between b ¯ 1 * b ¯ 2  and plane P,

a 2 = 2 5 1 1 ( n o t p o s s i b l e )

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