Class 12th

Get insights from 11.9k questions on Class 12th, answered by students, alumni, and experts. You may also ask and answer any question you like about Class 12th

Follow Ask Question
11.9k

Questions

0

Discussions

44

Active Users

0

Followers

New answer posted

8 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

l i m n ( n + 1 n ) k 1 1 n r = 1 n ( k + r n )

= 3 3 0 1 x k d x

New answer posted

8 months ago

0 Follower 13 Views

V
Vishal Baghel

Contributor-Level 10

f ( x ) = { | 4 x 2 8 x + 5 | , i f 8 x 2 6 x + 1 0 [ 4 x 2 8 x + 5 ] , i f 8 x 2 6 x + 1 < 0

x = 1 4 , 2 2 2 , 1 2

New answer posted

8 months ago

0 Follower 22 Views

V
Vishal Baghel

Contributor-Level 10

General term

= 1 5 C r ( t 2 x 1 5 ) 1 5 r ( ( 1 x ) 1 1 0 t ) r    

for term independent on t

2 (15 – r) – r = 0

r = 1 0          

T 1 1 = 1 5 C 1 0 * ( 1 x )

Maximum value of x (1 – x) occur at

x =  1 2

New answer posted

8 months ago

0 Follower 11 Views

V
Vishal Baghel

Contributor-Level 10

Here,

A = [ 2 1 1 1 0 1 1 1 0 ]            

we get A2 = A and similarly, for

B = A I = [ 1 1 1 1 1 1 1 1 1 ]            

We get B2 = -B  B3 = B

A n + ( ω B ) n = A + ( ω B ) n f o r n N

For ω n  to be unity n shall be multiple of 3 and for Bn to be B. n shell be 3, 5, 7, ….9

n = { 3 , 9 , 1 5 , . . . . . 9 9 }     

Number of elements = 17.

New answer posted

8 months ago

0 Follower 74 Views

V
Vishal Baghel

Contributor-Level 10

2 (only 2 carbon will chiral in product form)

New answer posted

8 months ago

0 Follower 8 Views

V
Vishal Baghel

Contributor-Level 10

  C o 3 +  will not get oxidized, so will not liberate H2 gas upon reaction with acidic solution.

No. of unpaired electron = 4

Spin only magnetic moment = 4 ( 4 + 2 ) B M = 2 4 B M 5 B M

New answer posted

8 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

Complex absorbing minimum wavelength of light means the value of Δ  for it is maximum.

That complex will be [ C o ( C N ) 6 ] 3

C o 3 + 3 d 6 4 s 0 t 2 g 6 e g 0

No. of unpaired electron = 0

New answer posted

8 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

( t 1 / 2 ) l ( t 1 / 2 ) I I = ( P I P I I ) 1 n n = 1

New answer posted

8 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

  A n o d e : ( Z n Z n 2 + + 2 e ) * x

C a t h o d e : ( S n x + + x e S n ) * 2 _      

Net call reaction :  x Z n + 2 S n x + x Z n 2 + + 2 S n ( n = 2 x )

Using Nernst equation

No. of electron involved = 4

New answer posted

8 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

d = 2 R h          

d = 2 * 6 4 0 0 * h * 1 0 3 ( h i n m )

Area =  π d 2

= ( π * 2 * 6 4 0 0 * h * 1 0 3 ) km2

h = 150m

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 66k Colleges
  • 1.2k Exams
  • 688k Reviews
  • 1850k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.