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Class 12th Biomolecules

A polysaccharide 'X' on boiling with dil H₂SO₄ ate 393 K under 2-3 atm pressure yields 'Y'. 'Y' on treatment with bromine water give gluconic acid. 'X' contains b-glycosidic linkages only. Compound 'X' is:

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Vishal Baghel

Contributor-Level 10

$C e l l u l o s e \to_{}^{H^{+} / H_{2} O} β - D - G l u c o s e \to_{W a t e r}^{B r_{2}} G l u c o n i c a c i d$

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Class 12th Maths

Let the lope of the tangent to a curve y = f(x) at (x,y) be given by 2 tan x (cos x – y). If the curve passes through the point $(\frac{π}{4}, 0),$ then the value of $\int_{0}^{π / 2} y d x$ is equal to:

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alok kumar singh

Contributor-Level 10

$\frac{d y}{d x} + 2 y t a n x = 2 s i n x$

$I . F . = e^{2 \int t a n x d x} = s e c^{2} x$

$∴$ Solution y sec²x = $2 \int s i n x s e c^{2} x d x = 2 \int s e c x t a n x d x$

y sec² x = 2sec x + c

y = 2 cos x + c cos²x passes $(\frac{π}{4}, 0) = B$ C = $- 2 \sqrt[]{2}$

y = 2 cos x $2 \sqrt[]{2} c o s^{2} x$ $∴ \int_{0}^{π / 2} y d x = 2 - \frac{π}{\sqrt[]{2}}$

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Class 12th Chemistry

Which of the following is an example of polyester?

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Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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Class 12th Chemistry Chemical Kinetics

For a first order reaction, the time required for completion of 90% reaction is 'x' times the half life of the reaction. The value of 'x' is

(Given : In 10 = 2.303 and log 2 = 0.3010)

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alok kumar singh

Contributor-Level 10

$T_{90 %} = \frac{2.303}{k} l o g \frac{100}{10}$

$T_{50 %} = \frac{2.303}{k} l o g \frac{100}{50}$

$\frac{T_{90 %}}{T_{50 %}} = \frac{l o g 10}{l o g 2} = \frac{1}{0.301} = 3.32$

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Class 12th Chemistry

The major product of the above reactions is:

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Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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Class 12th Chemistry

Which of the following is an example of conjugated diketone?

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Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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Class 12th Physics Atoms

In Bohr's atomic model of hydrogen, let K, P and E are the kinetic energy, potential energy and total energy of the electron respectively. Choose the correct option when the electron undergoes transitions to a higher level

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Payal Gupta

Contributor-Level 10

Based on theory

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Class 12th Physics Wave Optics

Two light beams of intensities in the ratio of 9 : 4 are allowed to interfere. The ratio of the intensity of maxima and minima will be

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Payal Gupta

Contributor-Level 10

$\frac{l_{1}}{I_{2}} = \frac{9}{4}$ $\frac{l_{m a x}}{l_{m a x}} = \frac{l_{1} + l_{2} + 2 \sqrt[]{l_{1} l_{2}}}{l_{1} + l_{2} - 2 \sqrt[]{l_{1} l_{2}}}$

$= \frac{\frac{9}{4} + 1 + 2 \sqrt[]{\frac{9}{4}}}{\frac{9}{4} + 1 - 2 \sqrt[]{\frac{9}{4}}}$

$= \frac{\frac{13}{4} + \frac{2 * 3}{2}}{\frac{13}{4} - 2 * \frac{3}{2}} = \frac{25}{1}$

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Class 12th Chemistry

Two statement are given below:

Statement I : The melting point of monocarboxylic acid even number of carbon atoms is higher than that of with odd number of carbon atoms acid immediately below and above it in the series.

Statement II : The solubility of monocarboxylic acids in water decreases with increases in molar mass.

Choose the most appropriate options

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Vishal Baghel

Contributor-Level 10

Melting point of monocarboxylic acids with even number of carbon is more than that with odd number of carbon due to lattice energy.

With increase in molar mass of monocarboxylic acids size of alkyl group (Hydrophobic portion) increases and therefore solubility in water decreases.

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