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New answer posted

11 months ago

0 Follower 8 Views

A
alok kumar singh

Contributor-Level 10

t 1 / 2 = 2 0 0 d a y s = 0 . 6 9 3 k

t = 2 . 3 0 3 k l o g 1 0 N 0 N

83 =  2 . 3 0 3 0 . 6 9 3 * 2 0 0 l o g N 0 N

8 3 = 2 0 0 0 . 3 0 1 0 l o g N 0 N

0.125 = l o g N 0 N

N 0 N = a n t i l o g ( 0 . 1 2 5 )

= 1.333

Activating remaining = N N 0 * 1 0 0

= N 0 1 . 3 3 3 N 0 * 1 0 0

= 75%

 

New answer posted

11 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

A 1 0 5 B + 1 1 5 C

Q = [ 1 0 5 * 6 . 4 + 1 1 5 * 6 . 4 ] [ 2 2 0 * 5 . 6 ] M e v

Q = 176 MeV

New answer posted

11 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

According to Rutherford, e- revolves around in nucleus in circular orbit. Thus e- is always accelerating (centripetal acceleration). An accelerating change emits EM radiation and thus e- should loose energy and finally should collapse in the nucleus.

New answer posted

11 months ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

Velocity of wave in a medium = 1 μ m m

v = 1 μ 0 μ r r 0 v = 3 * 1 0 8 1 . 6 1 * 6 . 4 4 = 0 . 9 3 1 * 1 0 8 m / s e c

B = μ m H = μ r μ 0 H = 1 . 6 1 * 4 π * 1 0 7 * 4 . 5 * 1 0 2 = 1 . 6 1 * 4 π * 4 . 5 * 1 0 9

E B = v

E = vB   = 0.931 * 108 * 1.61 * 4p * 4.5 * 10-9

= [0.931 * 1.61 * 4p * 4.5] * 10-1

= 8.476

» 8.476 v m-1

New answer posted

11 months ago

0 Follower 14 Views

A
alok kumar singh

Contributor-Level 10

E S n 2 + / S n 0 = 0 . 1 4 0 V = E 2 0

E S n 4 + / S n 0 = + 0 . 0 1 0 V = E 3 0

Here, Δ G 3 0 = Δ G 1 0 + Δ G 2 0

4 F E 3 0 = 2 F E 1 0 2 F E 2 0

E 3 0 = E 1 0 + E 2 0 2

+ 0 . 0 1 0 = E 1 0 + ( 0 . 1 4 0 ) 2

E 1 0 = E S n 4 + / S n 2 + 0 = + 0 . 1 6

= 16 * 10-2 V

 

New answer posted

11 months ago

0 Follower 9 Views

V
Vishal Baghel

Contributor-Level 10

Let l = l0 cos wt

l = l0, at t1 = 0

l = l 0 2 , a t ω t = π 4 t 2 = π 4 ω

t 2 = π 4 ω = π 4 * T 2 π = T 8           

t 2 = 1 8 * 1 υ ( T = 1 υ )           

t 2 = 1 8 * 5 0           

t 2 = 1 4 * 1 0 + 2             

= 0.25 * 10-2

t2 = 2.5 ms

New answer posted

11 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

qE = mg

q = m g E = 0 . 1 1 0 0 0 * 9 . 8 4 . 9 * 1 0 5         

q = 2 * 10-9 C

New answer posted

11 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

11 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Compound X is sucrose as,

Here, glucose is A which on oxidation with HNO3 gives saccharic acid as

B is b-D fructose which is laevarotatory.

New answer posted

11 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Natural rubber is a linear polymer of isoprene called cis-polyisoprene and has elastic properties.

Ci-polyisoprene molecule consists of various chains held together by weak vander Waals interactions and has a coiled structure.

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