Class 12th
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New answer posted
11 months agoLet lie on the plane px – qy + z = 5, for some The shortest distance of the plane form the origin is
Contributor-Level 10
Line to the normal
⇒ 3p + 2q – 1 = 0
lies in the plane 2p + q = 8
From here p = 15, q = -22
Equation of plane 15x – 22y + z – 5 = 0
Distance from origin = √5/142
New answer posted
11 months agoContributor-Level 10
B = (I – adjA)5
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New answer posted
11 months agoContributor-Level 10
Since current is in phase with voltage, it means circuit is in resonance, so we can write
f =
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