Class 12th

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New answer posted

11 months ago

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Payal Gupta

Contributor-Level 10

Line  to the normal

⇒ 3p + 2q – 1 = 0

(2, 1, 3) lies in the plane 2p + q = 8

From here p = 15, q = -22

Equation of plane 15x – 22y + z – 5 = 0

Distance from origin = |5152+ (22)2+12|=√5/142

New answer posted

11 months ago

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Payal Gupta

Contributor-Level 10

dy1+y2=2exdx1+ (ex)2+C

tan1y=2tan1ex+C

x = 0, y = 0

0=2tan1+C

C=+π2

now at x = ln3

tan1y=2tan1 (eln3)+π2

6 (y' (0)+ (y (ln3))2)=6 (1+13)=4

New answer posted

11 months ago

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Payal Gupta

Contributor-Level 10

 022xdx022xx2dx=01dy011y2dy02y22dy+122dy+I

83011t2dt=186+2+I

I=1011t2dt

New answer posted

11 months ago

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P
Payal Gupta

Contributor-Level 10

f (x)=x+x01f (t)dt01t0f (t)dt

Let 1+01f (t)dt=α

01tf (t)dt=β

So, f (x) = αx – β

Now, α=01f (t)dt+1

α=01 (atβ)dt+1

β=01tf (t)dt

β=413, α=1813

f (x) = αx – β

=18x413

option (D) satisfies

New answer posted

11 months ago

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Payal Gupta

Contributor-Level 10

f' (x)=n1f (x)x3+n2f (x)x5

=f (x) (n1+n2) (x3) (x5) (x (5n1+3n2)n1+n2)

f' (x)= (x3)n11 (x5)n21 (n1+n2) (x (5n1+3n2)n1+n2l)

option (C) is incorrect, there will be minima.

New answer posted

11 months ago

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Payal Gupta

Contributor-Level 10

 x42x3+2x1= (x1)2 (x21)

sinπx=sin (π (1x)

=sin (sinπ (x1))

limx1 (x21)sin2πx (x21) (x1)2=limx1sin2 (π (x1)) (x1)2

=limx1sin2 (π (x1)) (π (x1))2π2

= 2

New answer posted

11 months ago

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P
Payal Gupta

Contributor-Level 10

B = (I – adjA)5

fffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff

New answer posted

11 months ago

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Payal Gupta

Contributor-Level 10

Since current is in phase with voltage, it means circuit is in resonance, so we can write

f = 12πLC=12π (0.5*103)* (200*106)

f=1042π105*102Hz  [Takingπ=10]

New answer posted

11 months ago

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Payal Gupta

Contributor-Level 10

According to Young's double slit experiment, we can write

β=λDdΔβ=β2β1=λdΔD

λ=dΔβΔD=1*103*3*1055*102=60*108m=600nm

New answer posted

11 months ago

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Payal Gupta

Contributor-Level 10

According to Nuclear activity, we can write

N0t12N02t12N04t12N08t12N016= (0.0625)N0

Time required = 4 * t12=20yrs

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