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New answer posted

a year ago

0 Follower 9 Views

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Payal Gupta

Contributor-Level 10

l=∫−π2π2dx (1+ex) (sin6x+cos6x) ……. (i)

=2∫0∞dt4+t2=2 (tan−1 (t2))0∞=π

New answer posted

a year ago

0 Follower 61 Views

P
Payal Gupta

Contributor-Level 10

f (x)= {sin (x+2)x+2, x∈ (−2, −1)         0, x∈ (−1, 0]       2x, x∈ (0, 1)         1, otherwise

LHD=Lth→0f (0−h)−f (0)−h=0

RHD=Lth→0f (0+h)−f (0)h=2

Hence f (x) is not differentiable at x = 1, 0, 1

∴m=2, n=3

New answer posted

a year ago

0 Follower 3 Views

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Payal Gupta

Contributor-Level 10

x + y + az = 2………… (i)

3x + y + z = 4 ………… (ii)

x + 2z = 1 ……………. (iii)

x = 1, y = 1, z = 0

(for unique solution a ≠ − 3  

( α , − 1 ) , ( 1 , α ) a n d     ( 1 , − 1 ) are collinear.

α − 1 1 − α = − 1 − α 1 − 1 ⇒ 1 − α 2 = 0 ⇒ α = ± 1                

Sum of absolute value = 2

New answer posted

a year ago

0 Follower 6 Views

P
Payal Gupta

Contributor-Level 10

e2x−4=0   or   6e2x−5ex+1=0

⇒x=ln2x=ln (13), ln (12)

= −ln3, −ln2

New answer posted

a year ago

0 Follower 10 Views

P
Payal Gupta

Contributor-Level 10

given N = 1000 turns

A = 1m2

ω=1  rev/sec

=1*2π  rad/sec

V=−d? Bdt=−ddt (NB  A  cos  ωt)

= 140*227

= 20 * 22

= 440 volts

New answer posted

a year ago

0 Follower 12 Views

P
Payal Gupta

Contributor-Level 10

d=43 cm (Lateral shift)

By Snell's law

μairsin60°=μgsinθ

⇒1*32=3sinθ

sinθ=12

= 30°

tan30°=dt=43t

⇒13=43t

t = 12 cm

New answer posted

a year ago

0 Follower 6 Views

P
Payal Gupta

Contributor-Level 10

for  A, t12=4  sec

=mA0e−0.6934*16

mA=mA0e−4*0.693 - (1)

for B,

for B,  t12=8sec

mB=mB0e−2*0.693 - (2)

mAmB=mAOmBOe−4*0.693e−2*0.693

mAmB=25100=x100x=25

New answer posted

a year ago

0 Follower 13 Views

P
Payal Gupta

Contributor-Level 10

IL=VRL=51kΩ

lL=5*10−3A=5mA

New answer posted

a year ago

0 Follower 6 Views

P
Payal Gupta

Contributor-Level 10

AB = 10 m

RAB=20Ω

LAC=250  cm

= 2.5 m

l=2520+30

E=x10=2510

New answer posted

a year ago

0 Follower 5 Views

P
Payal Gupta

Contributor-Level 10

v=Cμrεr=3*1086.25*1=3*1082.5=1.25*108m/sec

As  fλ=f (5*10−3*4)=1.25*108⇒f=6.25  GHz

So,  f≈6.

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