Class 12th
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New question posted
a year agoNew answer posted
a year agoContributor-Level 10
Meq of NH3 = Meq of used H2SO4 = Meq of NaOH = 0.25 * 30 = 7.5
Millmoles of N = millimoles of NH3 = 7.5 (As n factor = 1)
Mass of nitrogen = 7.5 * 14 * 10-3 = 0.105 gm
% of Nitrogen =
New answer posted
a year agoNew answer posted
a year agoContributor-Level 10
ax + by + cz = d
2a + 3b – 5c = d 2a + 3b – 5c = d …………….(v)
Putting (i) & (iv) in (v) we get a = -9d.
In conditions
2b = d ………….(i) d > 0
2a + b – 5c = 0 2a + 3b – 5c = d
=
3a + 5b – 7c = 0) *
c = -7, d = 2
(iii)…(ii) ® 2a + 3b
2a + 3b =
Putting values
a + 7b + c + 20d = 22
New answer posted
a year agoNew question posted
a year agoTaking an Exam? Selecting a College?
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