Class 12th

Get insights from 12k questions on Class 12th, answered by students, alumni, and experts. You may also ask and answer any question you like about Class 12th

Follow Ask Question
12k

Questions

0

Discussions

59

Active Users

0

Followers

New answer posted

7 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

This is a assertion and reason answer type question as classified in NCERT Exemplar

Correct option is (iii)

HNO3 forms an oxide layer on the surface of iron. This is also known as corrosion or rusting.

New answer posted

7 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

This is a Short Answer Type Question as classified in NCERT Exemplar

Sol:

f(x)12cosx,xRRangeofcosxis[1,1]Letf(x)=y=12cosx2yycosx=1ycosx=2y1cosx=2y1y=21yNow1cosx1121y1121y1231y131y113y1therangeoff=[13,1].

New answer posted

7 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

This is a assertion and reason answer type question as classified in NCERT Exemplar

Correct option is (iii)

Nitrogen gas has a complete octet structure for both atoms and is unreactive due to the presence of a strong triple bond. On the other hand,  phosphor has bonds with unstable angles strains compared to nitrogen,  therefore it burns quickly,  thus readily reacts. Nitrogen has a lower electron gain enthalpy than phosphorus.

New answer posted

7 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

This is a Short Answer Type Question as classified in NCERT Exemplar

Sol:

Letx1,x2gof                                  

 gof{f(x1)}=gof{f(x2)}                             

g(x1)=g(x2)                             

 
x1 =x2

Hence,fisoneoneandgisonto.

New answer posted

7 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

Correct option is (i) and (ii)

(i) The modest dispersion force causes attraction in noble gases.

(ii) In nature, xenon fluorides are reactive.

New answer posted

7 months ago

0 Follower 1 View

P
Pallavi Pathak

Contributor-Level 10

Explanation- given d= 0.1nm,  ?  =300 and n=1

According to bragg's law

2dsin ?  ?

2 *0.1*sin30=?

? =0.1nm=10-10

? =hmv=hp

P=h/ ?   = 6.62*10-3410-10 = 6.62 *10-24 kgm/s

k.E= 1/2mv2= 12m2v2m p22m = 0.21eV

New answer posted

7 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

This is a Short Answer Type Question as classified in NCERT Exemplar

Sol:

Giventhat, 

X={1,2,3}andY={4,5}

X *?Y={(1,4),(1,5),(2,4),(2,5),(3,4),(3,5)}

(i)f={(1,4),(1,5),(2,4),(3,5)}

fisnotafunctionbecausefhasnouniqueimage.

(ii)g={(1,4),(2,4),(3,4)}

Since,gisafunctionaseachelementofthedomainhasauniqueimage.

(iii)h={(1,4),(2,5),(3,5)}

Itisafunctionaseachelementofthedomainhasauniqueimage.

(iv)k={(1,4),(2,5)}

kisnotafunctionas3doesnothaveanyimageunderthemapping.

New answer posted

7 months ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

Correct option is (ii) and (iii)

Here fig (b) contains one S-S bond.

The oxidising behaviour of H2SOis represented by (ii) and (iii) among the aforementioned four. It oxidises HI in reaction (ii) and then reduces to SO2.

The oxidation state of sulphur's core atom drops from +6 to +4. It oxidises copper in (iii) and is reduced to SO2.

 

New answer posted

7 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

This is a Short Answer Type Question as classified in NCERT Exemplar

Sol:

Givenfunction,f(x)=cosxxRLet[π2,π2]f(x)f(π2)=cos(π2)=cosπ2=0cos(π2)=cosπ2=0Butπ2π2,f(x)isnotoneone.Now,f(x)=cosx,xRisnotontoasthereisnopreimageforanyrealnumber.Whichdoesnotbelongtotheintervals[1,1],therangeofcosx.

New answer posted

7 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

Correct option is (i)

Oxidation state of S=+6

(iii) Iron oxide with K2O and Al2O3 is used to increase the rate of attainment of equilibrium in Haber's process.

(iv) Change in enthalpy is negative for the preparation of SO3 by catalytic oxidation of SO2.

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 66k Colleges
  • 1.2k Exams
  • 684k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.