Class 12th

Get insights from 12k questions on Class 12th, answered by students, alumni, and experts. You may also ask and answer any question you like about Class 12th

Follow Ask Question
12k

Questions

0

Discussions

59

Active Users

0

Followers

New answer posted

7 months ago

0 Follower 6 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

Correct option is (i)

The 'Brown Ring Test' is an identification and conformation test of the nitrate ion  (NO3- ) using conc. H2SO4 and newly produced FeSO4. Place the NO3-  containing sample in a test tube. Then, with gentle shaking, add conc H2SO4 dropwise, heat it briefly on a Bunsen burner, and add freshly made greenish FeSO4 Then, due to the creation of brown coloured  [Fe (H2O)5 (NO)]SO4 complex, a brown ring forms in that test tube.

New answer posted

7 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

This is a Long Answer Type Question as classified in NCERT Exemplar

Sol:

Giventhat:  
 A={1,2,3}and  R={(1,1),(2,2),(3,3),(1,2),(2,3),(1,3)}Here,1R1,2R2and3R3,So,Risreflexive.1R2but2R1or2R3but3R2,So,Risnotsymmetric.1R1and1R21R3,So,Ristransitive.Hence,thecorrectansweris(a).

New answer posted

7 months ago

0 Follower 8 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

Correct option is (i)

The N-N sigma bond (single bond) is weaker than the P-P sigma bond (single bond) due to the smaller size of nitrogen which increases the interelectronic repulsions and thus making the bond weaker. 

New answer posted

7 months ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

Correct option is (ii)

The valence electrons of nitrogen are two 2s and three 2p. Nitrogen can make three covalent bonds by sharing its three 2p electrons. Consider the NH3 molecule. The nitrogen atom, however, still contains a lone pair of electrons in the 2s orbital. It can take one bond by transferring these two electrons from the lone pair. Consider the NH4+ molecule.

As a result, nitrogen can create four different bonds.

New answer posted

7 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

Correct option is (i)

The single N-N bond is weak because of high interelectronic repulsion of the non-bonding electrons, owing to the small bond length. As a result the catenation tendency is weaker in nitrogen that is why it does not show allotropy

New answer posted

7 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

Correct option is (ii)

On heating, lead nitrate decomposes into lead monoxide, nitrogen dioxide, and oxygen.

2Pb (NO3)2→2PbO + 4NO2 + O2.

New answer posted

7 months ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

Correct option is (iii)

H3PO2 has one O-H group and two P-H bonds

The existence of a P-H link gives phosphorus oxyacids their reducing characteristics. It has a strong proclivity for releasing protons. As a result, it demonstrates a decreasing nature.

New answer posted

7 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

Correct option is (iii) H3PO4

When it reacts with a metal atom, it can produce three different forms of salts, referred known as the three series of salts.

H3PO4 + Na→NaH2PO4

NaH2PO4 + Na→Na2HPO4

Na2HPO4 + Na→Na3PO4

New answer posted

7 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

Correct option is (iii)

When heated with concentrated NaOH in an inert CO2 environment. It formsPH3

P4 + 3NaOH + 3H2O→PH3 + 3NaH2PO2

As we progress from the top to the bottom in a group, the basic character of hydrides reduces PHis basic than NH3.

New answer posted

7 months ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

Correct option is (iv)

The E-H bond dissociation energy of SbH3 is the lowest among the aforementioned compounds, it easily releases H, making it a strong reducing agent. The greater the lowering agent, the weaker the E-H bond.

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 66k Colleges
  • 1.2k Exams
  • 684k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.