Class 12th
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New answer posted
a year agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
PH3 is insoluble in water and cannot create hydrogen bonds with it, it forms bubbles, whereas NH3 dissolves because it is soluble in water and can form hydrogen bonds with it.
New answer posted
a year agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar

New answer posted
a year agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
4NH3 + 5O2
4NO + 6H2O
New answer posted
a year agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
SO3 generates a dense fog of sulphuric acid that does not condense quickly, it is not absorbed directly in water to form H2SO4.
New answer posted
a year agoContributor-Level 10
This is a long answer type question as classified in NCERT Exemplar
A = NH4NO2
B = N2
C = NH3
D = HNO3
(i) NH4NO2→N2 + 2H2O
(ii) N2 + 3H2→2NH3
(iii) 4NH3 + 5O2→4NO + 6H2O
4NO + O2→4NO2
3NO2 + H2O→2HNO3 + NO
New answer posted
a year agoContributor-Level 10
This is a long answer type question as classified in NCERT Exemplar
Here, 'A' is NO2 (Nitrogen dioxide)
'B' is N2O4 (dinitrogen tetraoxide)
'C' is N2O3 (dinitrogen trioxide)
A brown gas is produced when lead nitrate (II) is heated

2Pb (NO3)2
2PbO + 4NO2 + O2
2NO2
N2O4
2NO + N2O4
2N2O3
New answer posted
a year agoContributor-Level 10
This is a long answer type question as classified in NCERT Exemplar
'A' is S8 'B' is SO2 gas
S8 + 8O2
8SO2
2MnO4 – + 5SO2 + 2H2O → 5 SO42– + 4H+ + 2Mn2+
(violet) (colourless)
2Fe3+ + SO2 + 2H2O → 2Fe2+ + SO42– + 4H+
New question posted
a year agoNew answer posted
a year agoContributor-Level 10
The de Broglie wavelength depends on:
Planck's constant h (a universal constant),
velocity v of the particle
mass m of the particle.
New answer posted
a year agoContributor-Level 10
Photons do not have enough energy ( )to overcome the work function (? ) of the material below the threshold frequency.The energy per photon remains too low to liberate electrons even if the light intensity is increased, so photoelectric emission cannot occur.
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