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New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- b, d

Explanation- modulation index m= Am/Ac

If m>1 then Am>Ac

maximum modulation frequency mf= frequency deviation / maximum frequency of modulating wave

here if m>1 then it means overlapping of both sides resulting loss of information.

New answer posted

a year ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- a, b, c

Explanation- production of modulated wave is given by frequency of upper side band – frequency of lower side band so in first three cases it is clearly visible.

New answer posted

a year ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer-b, c, d

Explanation- height of tower= 240m

For line of sight communication maximum distance would be d= 2 R h

So d= 2 * 6.4 * 10 6 * 240  = 55.4km

So distance under this are communicable

New answer posted

a year ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- b, d

Explanation- wm=3KHz

And wc= 1.5MHz= 1500KHz

By using these two 1500 ? 3= 1503 and 1497

Bandwidth = 2wm= 2 * 3 = 6KHz

New answer posted

a year ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- a, b, d

Explanation- frequency is given by Vm=15KHz

So wavelength is given by ? = c v = 3 * 10 8 15 * 10 3 = 1 5 * 10 5 m

Also we know that l = ? / 4  = 5km

The audio signals are of low frequency waves. Thus, they cannot be transmitted through sky

Waves as they are absorbed by atmosphere.

If the size of the antenna is less than 5 km, the effective power transmission would be very

Low because of deviation from resonance wavelength of wave and antenna length.

New answer posted

a year ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Explanation-equation of modulating wave is, m (t)= Amsinwmt

Carrier wave equation is Cm (t)= (Ac+Amsinwmt)sinwct

 = Ac [1+ A m A c s i n w m t ]sinwct

Also A m A c = M

Cmt= (Ac+Ac * s i n w m t )sinwct

Ac * =K

Sinwmt= Vm

equation having phase

so equation is Ac+K2Vmt}+sinwct+ ? ]

New answer posted

a year ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- b

Explanation- it is represented by a diagram given below

New answer posted

a year ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- b

Explanation- Here, in this question, the frequency of modulated signal received becomes more, which is possible with the poor bandwidth selection of amplifiers.

This happens because bandwidth in amplitude modulation is equal to twice the

Frequency of modulating signal. But, the frequency of male voice is less than that of a female.

New answer posted

a year ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- c

Explanation- The device which follows square law is used for modulation purpose. Characteristics shown by (i) and (iii) corresponds to linear devices.

Characteristics shown by (ii) corresponds to square law device. Some part of (i) also

Follow square law.

Hence, (ii)and (iv) can be used for modulation.

New answer posted

a year ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- b

Explanation- frequency of career wave and frequency of amplitude modulated wave is same which is wc .

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