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Classification of Elements and Periodicity in Prop

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4 months ago

Classification of Elements and Periodicity in Prop Chemistry NCERT Exemplar Solutions Class 11th Chapter Three

Which of the following statements are correct? 

(i) Helium has the highest first ionisation enthalpy in the periodic table.

(ii) Chlorine has less negative electron gain enthalpy than fluorine.

(iii) Mercury and bromine are liquids at room temperature.

(iv) In any period, atomic radius of alkali metal is the highest.
0 Follower 34 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option (i), (iii)& (iv)

He with 1s2 electronic configuration has the highest electron gain enthalpy in the periodic table. In any period the alkali metals have the lowest effective nuclear charge in that particular period for which its atomic radius is the highest in that period.

New answer posted

4 months ago

Classification of Elements and Periodicity in Prop Chemistry NCERT Exemplar Solutions Class 11th Chapter Three

Which of the following elements will gain one electron more readily in comparison to other elements of their group?

(i) S (g)

(ii) Na (g)

(iii) O (g)

(iv) Cl (g)
0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option (i)& (iv)

Both S and Cl have the higher tendency to gain electrons in order to attain stable the nearest noble gas configuration i.e. of Argon.

New answer posted

4 months ago

Classification of Elements and Periodicity in Prop Chemistry NCERT Exemplar Solutions Class 11th Chapter Three

Which of the following sequences contain atomic numbers of only representative elements?

(i) 3, 33, 53, 87

(ii) 2, 10, 22, 36

(iii) 7, 17, 25, 37, 48

(iv) 9, 35, 51, 88
0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option   (i)& (iv)

The s-block elements and p-block elements together are called representative elements.

New answer posted

4 months ago

Classification of Elements and Periodicity in Prop Chemistry NCERT Exemplar Solutions Class 11th Chapter Three

Those elements impart colour to the flame on heating in it, the atoms of which require low energy for the ionisation (i.e., absorb energy in the visible region of spectrum). The elements of which of the following groups will impart colour to the flame?

(i) 2

(ii) 13

(iii) 1

(iv) 17
0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option (i) & (iii)

Alkali metals and alkaline earth metals have low ionization enthalpy.

New answer posted

4 months ago

Classification of Elements and Periodicity in Prop Chemistry NCERT Exemplar Solutions Class 11th Chapter Three

In the following questions two or more options may be correct.

Which of the following elements can show covalency greater than 4?

(i) Be

(ii) P

(iii) S

(iv) B
0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option (ii) & (iii)

Both P and S have vacant d-orbital for which they execute extended covalency.

New answer posted

4 months ago

Classification of Elements and Periodicity in Prop Chemistry NCERT Exemplar Solutions Class 11th Chapter Three

Electronic configurations of four elements A, B, C and D are given below:

(A) 1s2 2s2 2p6                     (B) 1s2 2s2 2p4

(C) 1s2 2s2 2p6 3s1            (D) 1s2 2s2 2p5

Which of the following is the correct order of increasing tendency to gain electron :

(i) A < C < B < D

(ii) A < B < C < D

(iii) D < B < C < A

(iv) D < A < B < C
0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option (i)

The electron gain enthalpy of 2p orbital is higher than that of the 3s orbital

New answer posted

4 months ago

Classification of Elements and Periodicity in Prop Chemistry NCERT Exemplar Solutions Class 11th Chapter Three

Comprehension given below is followed by some multiple choice questions. Each question has one correct option. Choose the correct option.

In the modern periodic table, elements are arranged in order of increasing atomic numbers which is related to the electronic configuration. Depending upon the type of orbitals receiving the last electron, the elements in the periodic table have been divided into four blocks, viz, s, p, d and f. The modern periodic table consists of 7 periods and 18 groups. Each period begins with the filling of a new energy shell. In accordance with the Arfbau principle, the seven periods (1 to 7) have 2, 8, 8, 18,

...more
0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option (iii) d-block

Lanthanum is the element with the atomic number 57 and it belongs to the d-block.

New answer posted

4 months ago

Classification of Elements and Periodicity in Prop Chemistry NCERT Exemplar Solutions Class 11th Chapter Three

The formation of the oxide ion, O2– (g), from oxygen atom requires first an exothermic and then an endothermic step as shown below:

O(g) + e– → O– (g) ; ∆ Hᶱ = – 141 kJ mol–1

O– (g) + e– → O2– (g); ∆ Hᶱ = + 780 kJ mol–1

Thus process of formation of O2– in gas phase is unfavourable even though O2– is isoelectronic with neon. It is due to the fact that,

(i) Oxygen is more electronegative.

(ii) Addition of electron in oxygen results in larger size of the ion.

(iii) Electron repulsion outweighs the stability gained by achieving noble gas configuration.

(iv) O– ion has comparatively smaller size than ox

...more
0 Follower 20 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option (iii)

High amount of energy has to be supplied in order to overcome the e- - e - repulsion that arises when O- gets converted to O2- by accepting an electron

New answer posted

4 months ago

Classification of Elements and Periodicity in Prop Chemistry NCERT Exemplar Solutions Class 11th Chapter Three

Which of the following is the correct order of size of the given species:

(i) I > I – > I +

(ii) I + > I – > I

(iii) I > I + > I –

(iv) I – > I > I+
0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option (iv)

I+ possess the highest effective nuclear charge whereas I- possess the least among the given species.

New answer posted

4 months ago

Classification of Elements and Periodicity in Prop Chemistry NCERT Exemplar Solutions Class 11th Chapter Three

The elements in which electrons are progressively filled in 4f-orbital are called

(i) Actinoids

(ii) Transition elements

(iii) Lanthanoids

(iv) Halogens
0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option (iii)

The lanthanoids which belong to the f-block elements are the elements where 4forbitals are filled progressively.

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