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New comment posted
8 years ago
4 Followers
334 Views
New answer posted
8 years ago
0 Follower
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Sunil SoniManagement & IT Consultant
Scholar-Level 18
Graduate degrees (B.Tech) offered by IITs are of four years duration. M.Tech is of two years duration. Some of IITs also offers 5 years integrated B.Tech-M.Tech programs in few subjects.
New answer posted
8 years ago
0 Follower
48 Views
Shaurya Singh
Guide-Level 13
No chance as the cutoff for SC category candidates at IIMs and IITs is around 70 percentile in CAT.
New answer posted
8 years ago
0 Follower
97 Views
Sunil SoniManagement & IT Consultant
Scholar-Level 18
Your chances to make into any IIM are very minimal.
New answer posted
8 years ago
1 Follower
57 Views
Roopika Merugu
Contributor-Level 7
No, if your percentile is below 75, then you cannot take admission in any IIT.
All the best.
All the best.
New answer posted
8 years ago
0 Follower
33 Views
Roopika Merugu
Contributor-Level 7
If you don't get a seat in IIT, then you can apply for other institutes like:
1. NIT.
2. IIIT.
3. SRM.
4. VIT.
5. LPU.
6. BITSAT.
All the best.
1. NIT.
2. IIIT.
3. SRM.
4. VIT.
5. LPU.
6. BITSAT.
All the best.
New answer posted
8 years ago
0 Follower
134 Views
N
NISHANT SIDANA SIDANA
Contributor-Level 6
You have got a good score with decent academic record and work experience. You stand a good chance to get admission in top 15 colleges.
All the best.
All the best.
New answer posted
8 years ago
0 Follower
88 Views
S
New question posted
8 years ago
0 Follower
53 Views
New answer posted
8 years ago
0 Follower
92 Views
Roopika Merugu
Contributor-Level 7
The answer is 1/3 sq units. Actually, in the given question, we have 2 equations i.e., y=mod x and y greater than or equal to x square. The graphs of both the equations are drawn and next solve the equations.
We get the common meeting points as (0,0) and (1,1). So integrate, the equation (mod x-x square) from 0 to1 and multiply it with 2 because the area we got is only the area that was covered in the 1st quadrant.
By multiplying, we get the area that is covered in the 2nd quadrant too. My suggestion is that when you get the equation with greater than or equal to or less than or equal to, solve the equation consider only one condition t
We get the common meeting points as (0,0) and (1,1). So integrate, the equation (mod x-x square) from 0 to1 and multiply it with 2 because the area we got is only the area that was covered in the 1st quadrant.
By multiplying, we get the area that is covered in the 2nd quadrant too. My suggestion is that when you get the equation with greater than or equal to or less than or equal to, solve the equation consider only one condition t
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