JEE Main

A safe score to get into an Indian Institute of Technology (IIT) through JEE Main is typically above the 97 to 98 percentile. This percentile range is crucial for securing admission to top branches like Computer Science, Information Technology, Software Engineering, and Electronics at the National Institutes of Technology (NITs). Candidates aiming for these sought-after branches and institutes need to target a percentile range of 97 to 98 to have a strong chance of admission based on current trends and expectations.

According to the information from DTU, having a JEE Main 2024 category rank of 9909 (SC category) enables access to a range of computing-related courses. These courses encompass areas such as Digital Electronics, Database Management Systems, Operating Systems Design, Computer Organization and Architecture, Algorithm Design and Analysis, Software Engineering, Theory of Computation, Artificial Intelligence, Computer Networks, and others. This diverse array of courses covers various aspects of computer Science and engineering, providing a holistic education in software development, IT systems, algorithms, and hardware components.

Based on the details provided, with a JEE Main 2024 rank of 7120 and belonging to the OBC-NCL category as a male candidate, you are likely eligible for admission to several National Institutes of Technology (NITs), including NIT Rourkela, NIT Tiruchirappalli, NIT Surathkal, NIT Warangal, and NIT Jamshedpur. The exact NIT you can secure admission to depends on the cutoff ranks for the OBC-NCL category, which may vary from year to year. However, with a rank around 7120, admission to these NITs should be feasible. It's advisable to refer to the most recent NIT admission information to confirm the specific options available to you.

Having an EWS rank of 8170 in JEE Main 2024 puts you in a favorable position for admission to several NITs. Generally, candidates with EWS ranks in this vicinity often secure admission in NITs such as Surathkal, Calicut, Warangal, and others. The candidates are advised to visit: JEE Main Rank Predictor 2024: Calculate JEE Rank From Percentile/Score to check for the college in which they are eligibile.

Admission in Harcourt Butler Technical University, (HBTU) Kanpur will be done on basis of merit of JEE Main examination result. A Candidate who is domicile of Uttar Pradesh i.e. he / she has passed the 10+2 qualifying examination from Institution located in U.P. is eligible for counselling . Defence quota is applicable and it has 5% seats reserved. The cutoff for chemical engineering for OBC category was 63232 last year and probably will not consider such a lower rank .

If it is a general rank then you can not get in it, especially CSE branch You can't get admission only if you use the home quota other branch you can get at this rank. If it is your category rank you can definitely get an NIT college CSE branch with home state quota that offers. To check for the college in which you are eligible, visit: JEE Main Rank Predictor 2024: Calculate JEE Rank From Percentile/Score.

Hey, At this rank aws 49,000 in JEE- 24 you can get admitted in some of GFTI like Punjab Engineering College chandigarh Ghani Khan Choudhary Institute of Engineering and Technology, Malda, West Bengal as per data available on the Josaa counseling website for more clearity you can also check their opening and closing rank at JOSAA website of all the courses by rank and your category hence you can select and see the branch, the colleges as per your rank.

Sorry but you won't be able to get any NIT with this marks as one must score at least 75 percent in the board examination to get into NIT or IIT.

Yes, easily you will get into any college you want even the best NIT with top branches. I wish you good luck.