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New answer posted
2 years agoBeginner-Level 3
No, JEE mains paper 1 score is not required to get admission in National Forensic Sciences University for B.Tech+M.Tech CSE. National Forensic University hasn't any provision for taking admission based on JEE score. They have individual entrence test. On basis of the score in the entrance they admit the students. Seats are allocated to candidates based on merit and entrance score. National Forensic Science University course admission requires candidates to take the NFSU entrance test (or NFAT).
New answer posted
2 years agoContributor-Level 10
Yes, one can get admission for B.Tech in Kerela with 52.95 percentile in Joint Entrance Examination (JEE)mains with state quota. To know more about the examination, admission process or other courses offered at Kerala, refer to the official websites or Shiksha.
New answer posted
2 years agoContributor-Level 10
Yes, it is possible to join a Bachelor of Technology (BTech) programme without appearing for the Joint Entrance Examination (JEE) in India. Many engineering colleges and universities have their own entrance exams or admission criteria for BTech programs. Some private colleges may also offer direct admission based on academic performance in qualifying exams.
New answer posted
2 years agoBeginner-Level 3
Yes, you can get Ctae Udaipur. Apply in REAP counselling and fill your course preference. Best wishes
New answer posted
2 years agoContributor-Level 9
The NTA has made it very clear that candidates are not allowed to raise objections in the JEE Main final answer key. The candidates' results are prepared using the JEE Main final answer key. No, candidates are allowed to raise objections in the JEE Main final answer kry. The option to raise objections is only available in the provisional answer key.
New question posted
2 years agoNew answer posted
2 years agoContributor-Level 9
According to the NTA PwD category's JEE Main 2023 cutoff data, the lowest cutoff is 0.0013527. The highest cutoff, 90.7788642, is for the general category. PwD applicants who achieve an NTA scorer higher than 0.0013527 are qualified to take the JEE Advanced exam to be admitted to IITs. 2023 saw a decrease in the PwD cutoff to 0.0013527 from 0.0031029 in 2022.
New answer posted
2 years agoBeginner-Level 5
Congratulation for getting excellent percentage in JEE . you can easily getting seat in NIT (National Institute of Technology). The seats are allotted on the basis of several categories that are prevalent like ST, SC, GEN, OBC, PWD. In this year admission is total 23954 seats will be offered at NIT. The NIT contains the total number of seats offered in the particular specializations for an NIT.
New answer posted
2 years agoContributor-Level 10
The JEE Mains results will be made available online by NTA via the official website. On its official website, the NTA has made available the JEE Main 2024 Paper 2 result. The JEE Main 2024 session 2 paper 2 result is available to candidates at jeemain.nta.ac.in. The application number and date of birth are the login credentials needed to get the JEE Main Paper 2 result in 2024. The JEE Main 2024 paper 2 toppers have also been revealed by NTA along with the results. On April 24, the NTA released the JEE Main 2024 Session 2 Paper 1 result. The JEE Main Result Login 2024 has been made available by NTA on the official websites jeemain.nta.
New answer posted
2 years agoContributor-Level 6
SASTRA University takes the cutoff for admission in B.TECH as follows-
If a student secures a JEE Main Score of 185 and normalized +2 total marks of 95%, the combined score of the student will be (0.25*185)+(0.75*95) = 117.50. They ask applicants to submit the JEE scores in the application form even if they are not qualified for the Advanced or they don't have the cut-off prescribed by MHRD. SASTRA does not use the CBSE cut-off for its admission but its own ranks calculated based on +2 marks and JEE (Main) scores.
As you have 90% in board exam you can easily get ECE branch at SASTRA University, Kumbakonam campus. But you should try
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