Maths

Get insights from 6.5k questions on Maths, answered by students, alumni, and experts. You may also ask and answer any question you like about Maths

Follow Ask Question
6.5k

Questions

0

Discussions

14

Active Users

0

Followers

New answer posted

2 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

So D = 0 → |, [1,3, k²], | = 0 ⇒ k² = 9
x + y + 3z = 0
x + 3y + 9z = 0
3x + y + 3z = 0
(1)- (3)
x = 0 ⇒ y + 3z = 0
y/z = -3
So x + (y/z) = -3

New answer posted

2 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

(-1+i√3)/ (1-i)³? = (2 (cos (2π/3) + isin (2π/3)/ (√2 (cos (-π/4) - isin (-π/4)³?
= (2³? (cos20π + isin20π)/ (2¹? (cos (-15π/2) - isin (-15π/2)
= (2¹? (1 + 0i)/ (0 + i) = -2¹? i

New answer posted

2 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

w = I + j - 3k
p = 3i - j + k
q = -3i + 2j + 4k
p * q = |i, j, k; 3, -1, 1; -3, 2, 4| = -6i - 15j + 3k
S.D. = |AD. (p * q)|/|p * q| = | (36+225+9)|/√ (36+225+9) = 3√30

New answer posted

2 months ago

0 Follower 7 Views

R
Raj Pandey

Contributor-Level 9

∫? (√ax - x²/a)dx = a²/6
⇒ (2/3)√a b^ (3/2) - b³/3a = a²/6
also area of ΔOQR = 1/2
(1/2)b² = 1/2 ⇒ b=1
Put in (i) ⇒ 4a√a - 2 = a³ ⇒ a? - 12a³ + 4 = 0

New answer posted

2 months ago

0 Follower 6 Views

R
Raj Pandey

Contributor-Level 9

Let z = α ± iβ be roots of the equation
So 2α = -b and α² + β² = 45, (α+1)² + β² = 40
So (α+1)² - α² = -5 ⇒ 2α+1 = -5 ⇒ 2α = -6
So b=6
Hence b² - b = 30

New answer posted

2 months ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

D = |0, 2, 1; 1, -1, 1; x', y', 1| = 0

New answer posted

2 months ago

0 Follower 5 Views

R
Raj Pandey

Contributor-Level 9

Let lim (x→0) [ (3x²+2)/ (7x²+2)]^ (1/x²) = e^ [lim (x→0) (1/x²) * (3x²+2)/ (7x²+2) - 1)] =

e^ [lim (x→0) (1/x²) * (-4x²)/ (7x²+2)] = e^ (-4/2) = e? ²

New question posted

2 months ago

0 Follower 1 View

New answer posted

2 months ago

0 Follower 6 Views

R
Raj Pandey

Contributor-Level 9

- π 2 , 0

At d y 1 - y 2 + d x 1 - x 2 = 0 s i n - 1 ? y + s i n - 1 ? x = c

Hence x = 1 2 , y = 3 2 c = π 2 s i n - 1 ? y = c o s - 1 ? x

New answer posted

2 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

= 1 56 * 277.85 = 496

± 1 = 1 1 λ 1 1 3 2 1 1 = - λ + 3 = ± 1 or λ = 2

For λ = 4

λ = 4

c o s ? θ = 2 + 1 + 4 6 18 = 7 6 3

 

 

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 65k Colleges
  • 1.2k Exams
  • 679k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.