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New answer posted

a year ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

0.50
 y = x²-3x+2, x+y=a, x-y=b
x?=2 x?=1
y? = 4-6+2 = 0 y?=0
(2,0)
(1,0)
b=2
a=1
∴ a/b = 1/2 = 0.5

New answer posted

a year ago

0 Follower 26 Views

A
alok kumar singh

Contributor-Level 10

OS = √S?
Radius = R = 2
Length of AB = (2RL)/√(L²+R²) = 16/√20
AB² = 64/5

 

New answer posted

a year ago

0 Follower 15 Views

V
Vishal Baghel

Contributor-Level 10

120.00
(1 + x + x² + x?)? = (1 + x)? · (1 + x²)?
Coefficient of x? = ?C?·?C? + ?C?·?C? + ?C?·?C?
= 15 + 90 + 15
= 120

New answer posted

a year ago

0 Follower 40 Views

V
Vishal Baghel

Contributor-Level 10

19.00
Only '2' in range → 1 function
one element out of 1, 3, 4 is in range with '2'
number of ways = ³C? * (3!/(2!1!)) * 2! = 18
(Select one from 1, 3, 4 and distribute among a, b, c)
Total function = 1 + 18 = 19

New answer posted

a year ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

Let point P be (2t, t²) and Q be (h,k).
h/3 = (2t)/3, k/3 = (-2+t²)/3

New answer posted

a year ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Probability (at most two machines will be out of service) = (3/4)³ . k
⇒ ?C?(1/4)?(3/4)? + ?C?(1/4)¹(3/4)? + ?C?(1/4)²(3/4)³ = (3/4)³ . k
⇒ 17/8 (3/4)³ = (3/4)³ . k
⇒ k = 17/8

New answer posted

a year ago

0 Follower 13 Views

V
Vishal Baghel

Contributor-Level 10

f(x) = (3x²+ax-2-a)e?
f'(x) = (3x²+ax-2-a)e? + e?(6x+a)
= e?(3x²+(a+6)x-2)
∴ x=1 is a critical point
∴ f'(1)=0
∴ 3+a+6-2=0
a = -7
∴ f'(x) = e?(3x²-x-2)
= e?(3x+2)(x-1)


∴ maxima at x = -2/3
∴ minima at x = 1

New answer posted

a year ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

A and B are independent events so P(A/B) = 1/3

New answer posted

a year ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

5+3+7+a+b = 25 ⇒ a+b=10
S.D. = √(((5²+3²+7²+a²+b²)/5) - 5²) = 2
√((a²+b²+83)/5) - 25 = 4 ⇒ a²+b² = 62
⇒ (a+b)² - 2ab = 62 ⇒ ab = 19
So equation whose roots are a and b is x² - 10x + 19 = 0

New answer posted

a year ago

0 Follower 17 Views

A
alok kumar singh

Contributor-Level 10

Let z = (3+isinθ)/(4-icosθ) x (4+icosθ)/(4+icosθ)
= (12 - sinθcosθ + i(4sinθ + 3cosθ))/(16 + cos²θ)
z is real
∴ 4sinθ + 3cosθ = 0
⇒ tanθ = -3/4 [? θ lies is 2nd quadrant]
arg(sinθ + icosθ) = π + tan?¹(cosθ/sinθ)
= π - tan?¹(4/3)

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