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3 months ago

Maths Quantitative Aptitude Prep Tips for MBA

Akshat's age is double that of Gaurav. The sum of the ages of Akshat and Gaurav is double that of Rishab. 6 years hence the sum of the ages of Akshat and Rishab will be three times the age of Gaurav. Find their present ages.

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Payal Gupta

Contributor-Level 10

Let the ages of Akshat, Rishab, Gaurav be X, Y, Z years respectively.

X = 2 Z . (1)

X + Z = 2 Y . (2)

(X + 6 + Y + 6) = 3 (Z + 6) &nb

...more

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New answer posted

3 months ago

Maths Quantitative Aptitude Prep Tips for MBA

In Rajdhani Express, there are 10 boggies which carries on an average of 20 passengers per boggie. If atleast 12 passengers were sitting in each boggie and no boggie has equal number of passenger then maximum, how many passenger can be accommodated in a boggie?

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Payal Gupta

Contributor-Level 10

Total number of passenger is the Rajdhani Express = 10 * 20 = 200

So, in the 9 boggies the minimum number of total passengers = 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 = 144

Hence, the minimum number of passenger in one boggie can be (200? 144) = 56

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3 months ago

Maths Quantitative Aptitude Prep Tips for MBA

A, B and C can alone do a work in 15 days, 20 days and 30 days, respectively. They work together for some time after which C leaves. A total of Rs. 18000 is paid for the work and B gets Rs. 6000 more than C. For how many days did A work?

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Payal Gupta

Contributor-Level 10

Let A and B work for m days and C for n days to complete the work. Therefore,

$\frac{m}{15} + \frac{m}{20} + \frac{n}{30} = 1$ . (1)

Out of the total of Rs. 18000, B gets Rs. 6000 more than C.

i.e., $\frac{m}{20} - \frac{n}{30} = \frac{6000}{18000} = \frac{1}{3}$ . (2)

On adding Eqs. (1) and (2), we get

$\frac{m}{15} + \frac{2 m}{20} = \frac{4}{5} \Rightarrow m = 8$

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New answer posted

3 months ago

Maths Quantitative Aptitude Prep Tips for MBA

A quadratic function f(x) attains a maximum of 3 at x = 1. The value of the function at x = 0 is 1. What is the value of f(x) at x = 10?

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Payal Gupta

Contributor-Level 10

Let f (x) = px²+ qx + k, where p, q and k are integers, and p ≠ 0

$∴$ f (0) = k = 1

$∴$ f (x) = px² + qx + 1

= px² +qx + k (Differentiate both sides with respect to x)

$∴$ f' (x) = 2px + q

For maxima or minima f' (x) = 0, x = $- \frac{q}{2 p}$

f (x) attains maximum at x = 1

$∴$ q = − 2p

f (1) = p + q + 1 = 3

$∴$ 1 − p = 3

$∴$ p = − 2

$∴$ q = 4

$∴$ f (x) = −2x² + 4x + 1

f (10) = − 200 + 40 + 1 = −159

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3 months ago

Maths Quantitative Aptitude Prep Tips for MBA

For which of the following values of a and b, f(x) = a – x² + 1 and g(x) = x² + b + 3 and f(2) g(1) < 0 holds true.

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Payal Gupta

Contributor-Level 10

f (x) = x – x² + 1

g (x) = x² + b + 3

f (2) g (1) < 0

(a – 4 + 1) (1 + 6 + 3) < 0

(a – 3) (b + 4) < 0

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3 months ago

Maths Quantitative Aptitude Prep Tips for MBA

How many zeroes will be there at the end of the number N, if N = 100! + 200!?

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Payal Gupta

Contributor-Level 10

100! has 24 zeroes.

100! + 200! = 100! [1 + 101 * 102 * … * 200]

Which will again give 24 zeroes at the end.

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New answer posted

3 months ago

Maths Quantitative Aptitude Prep Tips for MBA

A survey on a sample of 50 new cars being sold at a local auto dealer was conducted to see which of the three popular options – E1 engine, E2 engine and E3 engines were already installed. Following were the observation of the survey:

I. 30 had E1 engine

II. 4 had E1 engine and E3 engine but no E2 engine

III. 24 had E2 engine

IV. 12 had E1 engine and E2 engine but no E3 engine

V. 22 had E3 engine

VI. 8 had E2 engine and E3 engine

VII. 6 had all three options

What is the number of cars that had none of the options?

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Payal Gupta

Contributor-Level 10

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New answer posted

3 months ago

Maths Quantitative Aptitude Prep Tips for MBA

If P + Q + R + S = 1540 and 2P = 3Q = 4R = 5S, then what will be the difference between the values of R and S?

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Payal Gupta

Contributor-Level 10

Let 2P = 3Q = 4R = 5S = K

Then, $P = \frac{K}{2}, Q = \frac{K}{3}, R = \frac{K}{4}, S = \frac{K}{5}$

$\frac{K}{2} + \frac{K}{3} + = \frac{K}{4} + \frac{K}{5} = 1540$

K=1200

Therefore. R = 300, S = 240

Difference=300 - 240 = 60

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3 months ago

Maths Class 12th

The figure shows a cylindrical tube with a hemispherical bottom of radius 1 cm. if its length is 7 cm, find the capacity of the tube.

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Payal Gupta

Contributor-Level 10

Capacity of the tube

$π {(1)}^{2} (7 - 1) + \frac{2}{3} π {(1)}^{3} = \frac{20}{3} π$

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New answer posted

3 months ago

Maths Quantitative Aptitude Prep Tips for MBA

Given px² + qx + r = 0, pick out the incorrect statement from the following:

I. Roots are equal if q² = 4pr

II. Roots are equal but opposite in sign if q = 0

III. One root is reciprocal of the other if p = r

IV. Roots are complex if q² > 4pr

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Payal Gupta

Contributor-Level 10

If D < 0 roots are imaginary.

i.e. q² – 4pr < 0 $\Rightarrow$ q² < 4pr

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