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Maths Quantitative Aptitude Prep Tips for MBA

The nature of roots of equation $x^{2} - 2 \sqrt[]{5} x + 3 = 0$ is as follows

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Payal Gupta

Contributor-Level 10

Discriminant $= {(2 \sqrt[]{5})}^{2} - 4 (1) (3) = 20 - 12 = 8$

So, the roots are real and irrational.

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Maths Quantitative Aptitude Prep Tips for MBA

400 students were supposed to go to a camp for 100 days. After 20 days, 40% of the students left the camp. If the camp had food for all of them for 100 days, for how many more days will the food last than what was initially planned?

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Payal Gupta

Contributor-Level 10

400 students * 80 days = 240 students * d days

d = $\frac{400}{3} = 133.33 d a y s$

The food was to last 80 more days but now it is lasting 53.33 days more.

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Maths Quantitative Aptitude Prep Tips for MBA

Two metals A and B are to be used for making two different alloys. There are only 506 kg of A and 322 kg of B. If the ratio by weight of A to B in the first alloy is 5 : 3 and that in the second is 4 : 7, find what weight of each alloy must be produced so that no metal will be left over.

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Payal Gupta

Contributor-Level 10

	A	B
I	5x	3x
II	4y	7y

5x + 4y = 253 …. (1)

3x + 7y = 161 …. (2)

On solving equations (1) & (2), we get

x = 49 and y = 2.

Hence, type I Alloy = 392 kg, and Type II Alloy = 22 kg

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3 months ago

Maths Quantitative Aptitude Prep Tips for MBA

Two people start from opposite ends A and B of a corridor and move towards B and A respectively. When they meet for the first time, the respective distances covered by them is in the ratio 3 : 5 and one of them has covered 30 metres more than the other. If the speed of the person from A is 6 m/s, when will the person from B reach the end A after meeting with person from A?

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Payal Gupta

Contributor-Level 10

The distances covered by them are in the ratio 3:5 and difference is 30 m. This means 5x – 3x = 30 or 2x = 30 or x = 15 m

Therefore, the total distance covered is equal to 120 m. Their speeds are also in the ratio 3 : 5. Since the speed of the first person is 6 m/s, the speed of the second person will be 10 m/s and he has to cover a distance of 45 m.

Therefore time taken $= \frac{45}{10} = 4.5 seconds$

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3 months ago

Maths Quantitative Aptitude Prep Tips for MBA

Three solid metal spheres of radii 3 cm, 4 cm, 5 cm respectively, are melted together. The metal is recast as a single solid sphere. Find the percentage reduction in the area of surface resulting from this.

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Payal Gupta

Contributor-Level 10

Let R be the radius of the recast sphere

$\frac{4}{3} π R^{3} = \frac{4}{3} π (3^{3} + 4^{3} + 5^{3})$

R³ = 216 $\Rightarrow$ R = 6

Total surface area of 3 spheres

$= 4 π (3^{2} + 4^{2} + 5^{2}) = 4 π * 50 = 200 π^{}$

Surface area of the recast sphere = 4π (6²)=144

% reduction in area $= \frac{(200 π - 144 π)}{200 π} * 100 % = 28 %$

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3 months ago

Maths Quantitative Aptitude Prep Tips for MBA

In a geometric progression, product of 11th term, 18th term and 20th term is equal to the product of 28th term and 5th term. Which of the following is necessarily true about that geometric progression?

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Payal Gupta

Contributor-Level 10

ar¹⁰ * ar¹⁷ * ar¹⁹ = ar²⁷ * ar⁴

a³r⁴⁶ = a²r³¹

ar¹⁵ = 1

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3 months ago

Maths Quantitative Aptitude Prep Tips for MBA

What kind of triangle is formed by points (4,3), (6,-2) and (-11, -3)?

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Payal Gupta

Contributor-Level 10

Let A (4, 3), B (6, −2), C (−11, −3) be the vertices of triangle ABC.

AB² = (6 – 4)² + (−2 −3)² = 29

BC² = (−11 −6)² + [−3 – (−2)]² = 290

AC² = (−11 −4)² + [ (−3 −3)]² = 261

As AB²+ AC²= BC²

ABC is a right-angled triangle.

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3 months ago

Maths Class 12th

Find the equation of the line having the y-intercept equal to −3 and perpendicular to the line of equation 2x = 8 – 3y.

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Payal Gupta

Contributor-Level 10

Slope of given line = $- \frac{2}{3}$ perpendicular line has slope = $\frac{2}{3}$

Now c = −3 (given)

Putting in general equation y = mx + c

2y = 3x ⇒ 3x-2y=6

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3 months ago

Maths Quantitative Aptitude Prep Tips for MBA

The gross annual sales of a firm are Rs. 7500. The cost of materials and manufacture is 35% of the gross sales. Rent, rates and taxes amount to Rs. 772 ; advertising to Rs. 1880 ; office expenses to Rs 272 ; manager's salary Rs. 400 plus 1% of gross sales. Find the % profit.

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Payal Gupta

Contributor-Level 10

Total expenses = (35% of 7500) + 712 + 1880 + 272 + 400 + 75 = 6024

Total receipts = 7500 Total profit = 7500 – 6024 = 1476

% profit = $(\frac{1476}{6024}) * 100 = 24.5 %$

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3 months ago

Maths Quantitative Aptitude Prep Tips for MBA

Rs.1720 is divided among 45 persons consisting of men, women and children. The sum of men's, women's and children's shares are as 12 : 15 : 16 but the individual shares of a man, woman & child are as 6 : 5 : 4. Find respective share of 1 man, 1 women and 1 child.

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Payal Gupta

Contributor-Level 10

We can see that men, women & children are in the ratio = $\frac{12}{6}, \frac{15}{5}, \frac{16}{4},$ or 2: 3: 4.Number of men, women & children = 10, 15, 20. Now if each man gets 6a, we have10 * 6a + 15 * 5a + 20 * 4a = 1720 or a = 8. So, the answers are Rs. 48, 40, 32.

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