Ncert Solutions Chemistry Class 11th

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2 weeks ago

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A
alok kumar singh

Contributor-Level 10

The maximum prescribed concentration of manganese in drinking water is 0.05 ppm

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3 weeks ago

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P
Pallavi Pathak

Contributor-Level 10

In NEET exam, there can be 1 to 2 questions from redox reactions, carrying 4-8 marks. The weightage is around 2% to 4%. In JEE Main, the weightage of this chapter is from 3.3% to 4-6%. You can expect nearly 1 to 2 questions from this chapter.

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Pallavi Pathak

Contributor-Level 10

The applications of redox reactions include in cellular respiration, and batteries. In industries, these are used in the chemical production, metal extraction and water treatment. 

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Pallavi Pathak

Contributor-Level 10

The redox reactions are significant for some of the basic functions of life such as respiration, photosynthesis, corrosion or rusting and combustion.

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Pallavi Pathak

Contributor-Level 10

There are four types of redox reactions. These are combination, Decomposition, Displacement, and Disproportionation.
In the combination redox reaction, two or more substances form a single product, in decomposition reactions, a compound breaks down into two or more substances. When one element in a compound replaces another, it is called displacement reactions. When simultaneously, one substance is oxidized and reduced, the reaction is known as the disproportionation redox reaction.

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3 weeks ago

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Pallavi Pathak

Contributor-Level 10

In a chemical reaction when electrons transfer simultaneously between substances, it is called as the redox reaction.  In redox reaction, one substance gets oxidized by losing electrons and another substance reduces by gaining the electrons. These two processes together occurs in a redox reaction.

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V
Vishal Baghel

Contributor-Level 10

Moles of A I = 5.4 27 = 1 5

q = n C ? T = 1 5 * 24 * 30 = 144 J

 

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3 weeks ago

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V
Vishal Baghel

Contributor-Level 10

? G 0 = - 2.303 R T log ? K

= - 2.303 * R * 300 * log ? 10 10

= - 2.303 * 3000 R

=-6909 R

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3 weeks ago

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V
Vishal Baghel

Contributor-Level 10

N H 3 is recovered when solution containing N H 4 C l is treated with C a O H 2   (slaked lime).

2 N H 4 C l + C a O H 2 2 N H 3 + C a C l 2 + H 2 O .

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Vishal Baghel

Contributor-Level 10

u r m s 1 = 3 R T M

When the temperature is tripled,

u r m s 2 = 3 R ( 3 T ) M = 3 * u r m s 1 = 1.73 * u r m s 1

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