Ncert Solutions Chemistry Class 12th

the lowest spin only magnetic moment for Ni⁺² because of minimum unpaired electron.

For AB₃ interhalogen compound, which is T-shaped, only two lone pair electrons are available on central atom.

Electronic configuration of

Gd is ; Gd₆₄ = [Xe]4f⁷ 5d¹ 6s²

Hence $G{d}_{64}^{++}=\left[Xe\right]4f^{7}5d^{1}6s^0$

Total number of electrons in 4f sub-shell = 7

Ans. = 7

Molecular formula of Mohr' salt, FeSO₄. (NH₄)₂SO₄.6H₂O.

Molecular formula of potash alum = K₂SO₄.Al₂ (SO₄)₃.24H₂O. Overall molecular formula of potash alum = KAl (SO₄)₂. 12H₂O. Ratio of water molecules in Mohr' salt and Potash alum

$=\frac{6}{12}=\frac{1}{2}=0.5=5*10^{-1}$       

Ans. = 5

In electro-refining, impure metal (blister copper) is used as an anode while precious metal like Au, Pt gets deposited as anode mud.

Kindly consider the following figure

Reactivity order of halogens and inter halogens are F₂ > ClF > Cl₂ and ClF forms HOCl and HF after the reaction with water.

Statement-I is true, because metal reduced by decreasing $\Delta G$ in Elligham diagram but statement-II is false, Ellingham diagram is $\Delta G$ vs temperature graph has no relation with $\Delta S.$

  $\underset{Chlorocompound}{\underset{?}{A}}\underset{\left(2\right)H_{2}O}{\overset{\left(1\right)O_3}{\to }}Formaldehyde$

$\downarrow$                   

Weight = 1.53 gm

V = 448 ml (STP)

Mole = $\frac{448}{22400}=\frac{weight}{molecularweight}$

$\therefore \frac{1.53}{molecularweight}=\frac{1}{50}$  

$\therefore$ Molecular weight of compound A = 50 * 1.53 = 76.5 gram

Molecular weight 76.5 = C_nH_2n-1 Cl

$\therefore C_n{H}_{2n-1}=41$  

or 12 n + 2n – 1 = 41

Molecular formula = C₃H₅Cl

Number of C- atoms = 3

Kindly consider the following figure