Ncert Solutions Chemistry Class 12th

In Frenkel defect, cations are inserted in neighbouring site, therefore statement-I is correct, because vacancy developed by missing cations and interstitial sites are equal. Statement II is false because F-centre developed by metal excess defect due to anion vacancies.

$B{i}_2{S}_3?{\underset{2S}{2Bi}}^{+3}+{\underset{3S}{3S}}^{-2}$

$Ksp={\left(2S\right)}^2{\left(3S\right)}^3=4*27*{\left(S\right)}^5$

= 108 (S)5

${\left(S\right)}^5=\frac{1.08*10^{-73}}{108}=10^{-75}$ $\therefore S=10^{-15}M$

$E_{cell}={\left(E_{RHS}^o-E_{LHS}^o\right)}_{RP}-\frac{0.0591}{n}lo{g}_{10}Q$

$Q=\frac{\left[Z{n}^{++}\right]}{\left[C{u}^{++}\right]}=\frac{0.04}{0.02}andn=2$

$\therefore E_{cell}=\left(0.34+0.76\right)-\frac{0.0591}{2}lo{g}_{10}\frac{0.04}{0.02}$

$=1.1-\frac{0.0591}{2}*0.3010=1.091V=109*10^{-2}V$

Kindly consider the following figure

Cu₂Cl₂ + Water -> Insoluble

AgCl + Water -> Insoluble

ZnCl₂ + Water -> Colouless solution

CuCl₂ + Water -> Coloured solution due to 3d⁹ electronic configuration.

Molar weight of BaSO₄ = 233 gram

233 gm of BaSO₄ has 32 gm of S content

Hence 1.44 gm of BaSO₄ has $\left(\frac{32*1.44}{233}\right)$ g of S content = 0.1977 gm of 'S'

Weight of sulphur = 0.2 gram (the nearest)

Weight of organic sample = 0.471 gram

% of Sulphur = $\frac{0.2*100}{0.471}=42.46\mathrm{\%}$  

the nearest = 42%

Kindly consider the following figure

Yellow precipitate is Agl (s) which only produce by structure IV

${?}_0=h{\upsilon }_0$

$=6.6*10^{-34}*1.3*10^{15}J$

^{$=8.58*10^{-19}J$}

During adsorption of a gas on solid surface, process is exothermic i.e. $\Delta H=-ve\left(\Delta H<0\right)$  and entropy decreased, because gas particle resides on solid surface. Hence $\Delta S<0.$