Ncert Solutions Maths class 11th
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New answer posted
4 months agoContributor-Level 10
16 (i) Subset of {a} = {a}, .
(ii) Subset of {a, b} = ,{a},{b},{a, b}
(iii) Subset of {1,2,3} = ,{1},{2},{3}, {1,2}, {1,3}, {2,3}, {1,2,3}.
(iv) Subset of = .
New answer posted
4 months agoContributor-Level 10
15. (i) False as 3 A and 4 4. So, {3, 4} A.
(ii) True as {3, 4} A. i.e, {3, 4} is an element of A.
(iii) True as {3, 4} A so, {3, 4} A.
(iv) True as 1 is an element of A.
(v) False as 1 is not a set so it cannot be a subset of A.
(vi) True as 1 A, 2 A and 5 A. so, {1, 2, 5} A.
(vii) False as {1, 2, 5} is not an element of A.
(viii) False of 3 A.
(ix) False as is not an element of A.
(x) True, ? A as is a subset of every set.
(xi) False, as is not an element of A.
New answer posted
4 months agoContributor-Level 10
14. (i) False as every element of set {a, b} is also an element of {b, c, a} hence {a, b } { b, c, a }.
(ii) True as every element in {a, e} is also a vowel in English alphabet.
(iii) False as 2 {1, 2, 3} but 2 {1, 3, 5}.
(iv) True as a {a} is also a {a, b, c}
(v) False as a {a, b, c} but {a} {a, b, c}
(vi) {x : x is an even natural number less than 6} = {2, 4}
{x : x is a natural number which divides 36} = {1, 2, 3, 4, 6, 9, 12, 18, 36}
As {2, 4} {1, 2, 3, 4, 6, 9, 12, 18, 36}
It is true.
New answer posted
4 months agoContributor-Level 10
13. (i) {2,3,4} {1,2,3,4,5}
(ii) {a, b, c} ? {b, c, d}
(iii) {x : x is a student of class XI of yours school} {x : x is a student of your school}
(iv) As any circle in the plane can have radius more or less than 1 unit.
(x : x is a circle in the plane) ? {x : x is a circle in the same plane with radius 1 unit}
(v) As a triangle can never be a rectangle.
{x : x is a triangle in a plane} ? {x : x is a triangle in the same plane}
(vi) Any triangle in a plane can be scaler, isosceles, equilateral.
So. {x : x is a equilateral triangle in a plane} {x : x is a triangle in the same plane}
(vii) As all eve
New answer posted
4 months agoNew answer posted
4 months agoContributor-Level 10
11. (i) A = {2, 3)
B = {x : x is solution of x2 + 5x + 6 = 0}
So, x2 + 5x + 6 = 0
x2 + 2x + 3x + 6 = 0
x (x+2) + 3 (x+2) = 0
(x+2) (x+3) = 0
x = –2, –3
So, B = {–2, –3}
So, A ≠ B.
(ii) A = {x : x is a letter in word FOLLOW}
A = {F, O, L, W}
(iii) B = {x : x is a letter in word WOLF}
B = {W, O, L, F}
So, A = B as the elements are all same.
New answer posted
4 months agoContributor-Level 10
10. (i) As A and B has a, b, c and d as elements and are exactly the same, Hence, A = B.
(ii) Hence, 12 A but 12 B
Similarly 18 B but 18 A.
So, A ≠ B.
(iii) A = {2,4,6,8,10} and B = {2,4,6,8,10}
So, A=B.
(iv) A= {10,20,30,40, …} and B= {10,15,20,25,30, …}
So, A ≠ B.
New answer posted
4 months agoContributor-Level 10
9. (i) We can draw infinite number of lines parallel to x-axis.
∴ The set is infinite.
(ii) There are 26 letters in the English alphabet.
∴ The set is finite.
(iii) There are infinite number which are a multiple of 5.
∴ The set is infinite
(iv) The numbers of animals living on earth are finite.
∴ The set is finite.
(v) There can be infinite number of circular passing through origin (0,0).
∴ The set is infinite.
New answer posted
4 months agoContributor-Level 10
8. (i) The set of months of a year has 12 elements. Here, the set is finite.
(ii) The given set has the natural number as its elements. Hence, the set is infinite.
(iii) The given set has 100 elements i.e., from 1 to 100. Hence, the set is finite.
(iv) There are infinite numbers of positive integers greater than 100. Hence the set is infinite.
(v) The numbers of prime number less than 99 is finite. Hence, the set is finite.
New answer posted
4 months agoContributor-Level 10
1. (i) There is no odd number that can be divided by 2.
?The given set is a null set.
(ii) An even prime number is 2. Hence, the set will have 2 as element.
? The given set is not a null set.
(iii) As there is no natural number which is both less than 5 and greater than 7.
? The given set is a null set.
(iv) Two parallel lines never meets and hence no common point.
? The given set is a null set.
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