ncert solutions physics class 11th

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New answer posted•a year ago
S
a year ago

velocity of a freely falling body is v= 2gh

And ? =hmv=hm2gh

? =h -1

 The wavelength of a photon needed to remove a proton from a nucleus which is bound to the nucleus with 1 MeV energy is nearly
a) 1.2 nm (b) 1.2 x 10-3 nm
(c) 1.2 x 10-6  nm (d). 1.2 x 10 nm

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New answer posted•a year ago
S
a year ago

(d)

We can write

OS + PS > OP …….(i)

OS > PS – OP …….(ii)

a?-b? > a? + b? ….(iii)

The quantity on the LHS is always positive and that on the RHS can be positive or negative. To make both quantities positive, we take modulus of both sides as:

a?-b? > a?-b? ….(iv)

If the two vectors 

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New answer posted•a year ago
S
a year ago

6.30 The decay process of free neutron at rest is given as:

n ? p+e?

From Einstein's mass-energy relation, we have the energy of electron as?  mc2 where,

? m = Mass defect = Mass of neutron – ( Mass of proton + mass of electron)

c = speed of light

? m and c are constant. Hence, the given two-body

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New answer posted•a year ago
S
a year ago

6.29 The potential energy of two masses in a system is inversely proportional to the distance between them. The potential energy of the system of two balls will decrease as they get closer to each other. When the balls touch each other, the potential energy becomes zero, I.e. at r = 2R. The potentia

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New answer posted•a year ago
S
a year ago

6.28 Mass, m = 200 kg

Speed, v = 36 km/h = 10 m/s

Mass of the boy, M = 20 kg

Initial momentum = (M + m)v = (20 + 200) x 10 kg-m/s = 2200 kg-m/s

If v' is the final velocity of the trolley, then

The final momentum = (M+m) x v' – M x 4= 220v'-80

According to the law of conservation of energy,

Initial momentu

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New answer posted•a year ago
S
a year ago

6.27 Mass of the bolt, m = 0.3 kg, Height of the elevator, h = 3 m

Since the bolt did not rebound, the entire potential energy got converted into heat.

The potential energy of the bolt = mgh = 0.3 x 9.8 x 3 J = 8.82 J

The heat produced will remain same even if the lift is stationary, since g = constant

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New answer posted•a year ago
S
a year ago

6.26 Mass of the block = 1 kg

Spring constant = 100 N/m

Displacement of the block, x = 10 cm = 0.1 m

At equilibrium, normal reaction, R = mgcos? 37°

Frictional force, F = ? R = mgsin? 37°

Net force acting on the block down on the incline = mgsin? 37° - F

= mgsin? 37° - ? mgcos? 37°

=mg ( sin? 37°-? cos? 37° )

At equilibrium,

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New answer posted•a year ago
S
a year ago

6.25 From the law of conservation of energy,

the potential energy at the top = Kinetic energy at the bottom

mgh = (1/2)m v12 ….(1)

and

mgh = (1/2)m v22 ….(2)

v1 = v2 , Both the stones will reach with the same speed

For stone 1, the force acting on the stone 1 is given by , F1&n

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New answer posted•a year ago
S
a year ago

6.24 Mass of the bullet, mb = 0.012 kg

Initial speed of the bullet, u = 70 m/s

Mass of the wooden block , mw = 0.4 kg

Initial speed of the wooden block = 0

Let’s assume, final speed of the bullet = v

Applying the law of conservation of momentum

mb×u+mw×0=mb+mwv

Hence v = ( mb×u)/mb+mw = 2.04 m/s

Let h be the

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New answer posted•a year ago
S
a year ago

6.23 Power used by the family = 8 kW = 8000 W

(a) Solar energy received = 200 W/ m2

Percentage conversion of Solar energy to Electrical energy = 20%

If the area required is A then 0.2 *A*200=8000

A = 200 m2 . The comparable roof size is 14.14 X 14.14 m

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