ncert solutions physics class 11th

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New answer posted

4 months ago

0 Follower 6 Views

P
Payal Gupta

Contributor-Level 10

6.23 Power used by the family = 8 kW = 8000 W

(a) Solar energy received = 200 W/ m2

Percentage conversion of Solar energy to Electrical energy = 20%

If the area required is A then 0.2 *A*200=8000

A = 200 m2 . The comparable roof size is 14.14 X 14.14 m

New answer posted

4 months ago

0 Follower 9 Views

V
Vishal Baghel

Contributor-Level 10

Ans.4.21:

(a) Velocity , v? = 10.0 ? m/s

Acceleration, a? = (8.0 ? + 2.0 ?) m s-2

We know a? = dv?dt = 8.0 ? + 2.0 ?

dv? = (8.0 ? + 2.0 ?)dt

Integrating both sides we get v? (t) = 8.0t ? + 2.0t ? + u? ,

Where, u?= velocity vector of the particle at t =0

v?= velocity vector of the particle at time t

But v? = ?drdt

dr? = v? dt

= (8.0t ? + 2.0t ? + u? )dt

Integrating both sides with the condition at t = 0, r =0 and at t =t, r = r

r?= u? t + ½ * 8.0 t2 ? + ½ * 2.0 * t2 ? = u? t + 4.0 t2 ? + t2 ?

Substituting the value of u? , we get

r?= ( 10.0 ?)t + 4.0 t2 ? + t2 ? . This equation can be expressed as

x ? + y ? = 4.0 t2 ? + ( 10.0t + t2) ?

Since the motion of the particle is confined to the x-y plane, on equating the coefficients of ? and ?, we get

x = 4.0 t2 and y = 10.0t + t2

t = x/4

(a) When x = 16m, t = 2 s, y = 24m

(b) Velocity of the particle

v? (t) = 8.0t ? + 2.0t ? + u?

At t = 2 s,

v? (t) = 8.0 * 2 ? + 2.0 *2 ? + 10 * ? = 16 ? + 14 ?

The magnitude of v? (t) is given by

v? = ( 162 + 142)1/2 = 21.26 m/s

New answer posted

4 months ago

0 Follower 303 Views

V
Vishal Baghel

Contributor-Level 10

4.25

Height of the aircraft from the ground = 3400m

Let A and B be the positions of the aircraft, making an angle of AOB = 30 ° . The perpendicular OC and OC is the height of the aircraft. Angles AOC = angle BOC = 15 °

In AOC, AC = OC tan
15°
 = 3400 tan? 15° = 911.03m

AB = AC + CB = 2AC = 1822m

The distance of AB is covered in 10s, so the speed of the aircraft = 1822/10 m/s = 182.2 m/s

New answer posted

4 months ago

0 Follower 88 Views

V
Vishal Baghel

Contributor-Level 10

4.24

(a) Despite being a scalar quantity, energy is not conserved in elastic collisions. False

(b) Despite being a scalar quantity, the temperature can take negative values. False

(c) The total path length is a scalar quantity. Yet it has the dimension of length. False

(d) A scalar quantity such as gravitational potential can vary from one point to another point in space. False

(e) The value of a scalar does not vary for observers with different orientation of axis. True

New answer posted

4 months ago

0 Follower 93 Views

V
Vishal Baghel

Contributor-Level 10

4.23

(a) For any arbitrary motion of a particle average velocity cannot be expressed by this equation. False

 

(b) The arbitrary motion of the particle can be represented by this equation, True

 

(c) For arbitrary motion of the particle, the acceleration may also be non uniform. False

 

(d) The motion of the particle is arbitrary, acceleration of the particle may also be non-uniform, so can not represent the motion of the particle in space. False

 

(e) The arbitrary motion of the particle can be represented by the given equation. True

New answer posted

4 months ago

0 Follower 9 Views

C
Chandra Pruthi

Beginner-Level 5

Significance of de Broglie's Hypothesis in Modern Physics (NCERT-based answer):

De Broglie's hypothesis is a revolutionary idea which changed the understanding of matter and wave as we know it. This hypothesis introduced the concept that particles of matter, like electrons, and Proton, can behave like wave and have wave-like properties, just as light exhibits both wave and particle nature.

According to de Broglie, any moving particle has a wavelength given by:

? =hp=hmv\lambda = \frac {h} {p} = \frac {h} {mv}

where ? \lambda is the wavelength, hh is Planck's constant, mm is the mass, and vv is the velocity of the particle.

New answer posted

4 months ago

0 Follower 59 Views

A
alok kumar singh

Contributor-Level 10

2.3 

1 Calorie = 4.2 J = 4.2 kgm2s-2

Standard formula for conversion

Given unit / New unit = (M1/M2)x (L1/L2)y (T1/T2)z

Formula for energy = M1L2T-2

Here x = 1, y = 2, z = -2

In this problem

M1 = 1 kg, L1 = 1 m, T1 = 1 s and

M2 =? kg, L2 =? m, T2 =? s

So 1 Calorie = 4.2 (1/? )1 (1/? )2 (1/? )-2

= 4.2? -1? -2? 2

New answer posted

4 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Ans.2.1

(a) The volume of a cube of side 1 cm3 is equal to 10-6m3

The volume of the cube = 1 cm * 1 cm * 1 cm = 1 cm3

1 cm3 = 1 * 10-6 m3

(b) The surface area of a solid cylinder of radius 2.0 cm and height 10.0 cm is equal to1.25 * 104 (mm)2

The surface area of a solid cylinder = 2? r (r+)h, where r = 2.0 cm = 20 mm, h = 10 cm = 100 mmSurface area = 2 * 22/7 * 20 * (100 +20) mm2 = 1.51 * 104 mm2

(c) A vehicle moving with a speed of 18 km h–1 covers 5 m in 1 s

Vehicle speed = 18 km/h = 18000/3600 m/s = 5 m/s

(d) The relative density of lead is 11.3. Its density is 11.3 g cm–3 or 11.3 * 103.kg m–3.

Relative density or

...more

New answer posted

5 months ago

0 Follower 2 Views

P
Pallavi Pathak

Contributor-Level 10

8.12

Mass of the Sun, Ms = 2*1030 kg, Mass of the Earth, Me = 6*1024 kg

Orbital radius, r = 1.5*1011 m

Let the mass of the rocket be, m

Let x be the distance from the centre of the Earth where the gravitational force acting on satellite P becomes zero.

From Newton's law of gravitation, we can equate gravitational forces acting on the satellite P under the influence of the Sun and the Earth as:

GmMs(r-x)2 = GmMex2 or( r-xx)2 

MsMer-xx)2 = 2*10306*1024 ,

 r-xx = 577.35 , r = 578.35x ,

x = 1.5*1011578.35 = 2.59 *108 m

New answer posted

5 months ago

0 Follower 1 View

P
Pallavi Pathak

Contributor-Level 10

Ans.8.1

(a) No. Unlike electrical forces, gravitational force is independent of the status of the objects.

 

(b) Yes, the size of the space station is large enough and the astronaut will detect the change in Earth's gravity.

 

(c) Tidal effect depends inversely upon the cube of the distance while gravitational force depends inversely on the square of the distance. Since the distance between the Moon and the Earth is smaller than the distance between the Sun and the Earth, the tidal effect of the Moon's pull is greater than the tidal effect of the Sun's pull.

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