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New answer posted

7 years ago

0 Follower 496 Views

Shiksha Ask & Answer
Sujeet KumarPreparing for UPSC CSE 2021

Guide-Level 15

In CSAB rounds, you will be given NIT/IIIT according to your category rank if applicable, or else, General.

New answer posted

7 years ago

0 Follower 71 Views

Shiksha Ask & Answer
Nikhil GargFUTURE ENGINEER

Contributor-Level 9

You can check the previous year's cutoff's at
https://josaa.nic.in/josaaorcrarchieve/Result/OpeningClosingRankArchieveN.aspx?Year=2017
Generally homestate NITs are easier to get than that of the other states. REGISTRATION FOR THE COUNSELLING HAS BEEN STARTED FROM TODAY AND WILL BE OPEN TILL 25 JUNE 2018. BEST OF LUCK!

New answer posted

7 years ago

0 Follower 13 Views

Shiksha Ask & Answer
Nikhil GargFUTURE ENGINEER

Contributor-Level 9

On the basis of JEE main rank, you could get a seat in NITs and IIITs but not in IITs. You should visit
https://josaa.nic.in/josaaorcrarchieve/Result/OpeningClosingRankArchieveN.aspx?Year=2017
and check the previous year's cutoff's of your HOMESTATE NIT first and then the other NITs you want. There you would get an idea of your selection. ALSO, THE REGISTRATION FOR COUNSELLING HAS BEEN STARTED FROM TODAY AND WILL BE AVAILABLE UPTO 25 JUNE 2018. So take care of the important dates also. BEST OF LUCK!

New answer posted

7 years ago

0 Follower 30 Views

Shiksha Ask & Answer
Manish Motwani

Guide-Level 14

Since NITs are tough, among NIT-Patna, Bhopal, Jaipur, Kozhikode and Calicut, try for each with only home state quota. Else, go for Private Universities offering B.Arch and B.Planning.

New answer posted

7 years ago

0 Follower 39 Views

Shiksha Ask & Answer
Manish Motwani

Guide-Level 14

I would suggest you to again acknowledge your rank as it's not likely to have such a huge difference in the category and General Rankings. Moreover, till then, use our college predictor to better explore the opportunities:
https://www.shiksha.com/b-tech/resources/jee-mains-college-predictor?utm_source=cconnect&utm_medium=CR_JEECP&utm_campaign=6375912

New answer posted

7 years ago

0 Follower 336 Views

Shiksha Ask & Answer
Manish Motwani

Guide-Level 14

Sorry, but all NIT admissions close down to at maximum All India rank of 60000 for freshers batch. Rest rankings are for assuring students, their seats in JEE Advanced. Also, for any NIT, the minimum rank required for CS/IT is 15000 all India. Kindly go for state government autonomous institutes with home state quotas or private universities.
Best of luck.

New answer posted

7 years ago

0 Follower 62 Views

Shiksha Ask & Answer
Mohammed Faraz

Contributor-Level 10

You may try for JoSAA counselling but it's quite difficult to find a seat in a government architecture institution as they close within 2000 for SC,ST or OBC category.

New answer posted

7 years ago

0 Follower 35 Views

Shiksha Ask & Answer
Ritik AgiwalHard worker , learner .

Guide-Level 14

Hello,
I hope you are doing well. Yes, you have chances for NIT in MNIT, Jaipur for B.Tech with your rank. Please check the cutoff for MNIT under OBC category for different branches
- Chemical Engineering - 4220 - 6997
Civil Engineering - 2735 - 4514
CSE - 558 to 1827
Electrical engineering - 1536 to 2855
Electrical and communication - 2163 to 3960.

New answer posted

7 years ago

0 Follower 58 Views

Shiksha Ask & Answer
Manish Motwani

Guide-Level 14

It is not an NIT and IIIT, though. It can be said a GFTI as it was opened prior to Independence by government funds and a few organizations of Bengal.
Moreover, this institute is considered as an institute of national importance and it is mentor institute of IIIT-Kolkata.

New answer posted

7 years ago

0 Follower 15 Views

Shiksha Ask & Answer
Group Captain Vinayak DeodharLa vie est faite pour vivre pas pour stresser

Scholar-Level 18

Hello, Your rank is quite good. Roughly one fourth of 12K vacancies are reserved for OBC-NCL. So, up to rank of 3K admission is assured. But do not worry. I am attaching a link that will predict college for you. https://www.shiksha.com/b-tech/resources/jee-advanced-rank-predictor.

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