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Physics Laws of Motion

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Physics Laws of Motion Class 11th

A mass of 1 kg is suspended by a thread. It is lifted up with an acceleration of 4.9 ms^–2, and then lowered with an acceleration of 4.9 ms^–2 . The ratio of tensions in first case to second cases is (g = 9.8 ms^–2 )

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alok kumar singh

Contributor-Level 10

T₁ = m (g + a)

T₂ = m (g - a)

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Physics Laws of Motion Laws of Motion

A block rests on an inclined plane making an angle of 30° with the horizontal. The coefficient of static friction between block and the plane is 0.8. If the frictional force on the block is 10 N, then mass of block (in kg) (Take g = 10 m/s² )

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alok kumar singh

Contributor-Level 10

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Physics Laws of Motion Laws of Motion

Bullets of 0.03 kg mass each hit a plate at a rate of 200 bullets per second with velocity of 50 m/s and reflect back with velocity of 30 m/s. The average force acting on the plate in newton is

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alok kumar singh

Contributor-Level 10

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3 days ago

Physics Laws of Motion Laws of Motion

The root mean square speed of molecules of a gas is 1260 m/s. The average speed of the gas molecules is

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alok kumar singh

Contributor-Level 10

= 0.92 * 1260 = 1161 m/s

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a week ago

Physics Laws of Motion Class 11th

Ball released from height 10 m strikes ground and rebounds height 5 m. Find impulse imparted by ground while collision, given mass of ball is 100 g. (Take g = 10 m/s²)

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alok kumar singh

Contributor-Level 10

$v_{1} = \sqrt[]{2 g 10}$

$v_{2} = \sqrt[]{2 g 5}$

$\vec{l} = Δ \vec{p}$

$l = 0.1 {\sqrt[]{2 g 10} + \sqrt[]{2 g 5}}$

$= 0.1 {10 \sqrt[]{2} + 10}$

$= (\sqrt[]{2} + 1) N s$

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a week ago

Physics Laws of Motion Laws of Motion

Find the acceleration of 2 kg block shown in the diagram. (neglect friction)

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alok kumar singh

Contributor-Level 10

For 2 kg block

T – 2g sin37 = 2a . (i)

For 4 kg block

4g – 2T = $\frac{4 a}{2}$

2g – T = a . (ii)

T = (2g – a)

2g – a – 2g * $\frac{3}{5}$ = 2a

3a = 2g * $\frac{2}{5}$

$a = \frac{4 g}{15}$

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a week ago

Physics Laws of Motion Laws of Motion

In the system shown below, the pulley 4 string are ideal. If the acceleration of blocks is $\frac{g}{8}$ , find $\frac{m_{1}}{m_{2}}$

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alok kumar singh

Contributor-Level 10

$a = \frac{(m_{1} - m_{2}) g}{(m_{1} + m_{2})} = \frac{g}{8}$

8m₁ – 8m₂ = m₁ + m₂

7m₁ = 9m₂

$\frac{m_{1}}{m_{2}} = \frac{9}{7}$

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a week ago

Physics Laws of Motion Laws of Motion

For the block shown, F₁ is the minimum force required to move block upwards and F₂ is the minimum force required to prevent it from slipping, find $| {\vec{F}}_{1} - {\vec{F}}_{2} |$

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alok kumar singh

Contributor-Level 10

f_K = μmg cosq

= 0.1 * $\frac{50 * \sqrt[]{3}}{2}$

$= 2.5 \sqrt[]{3} N$

F₁= mg sinq + f_K

= 25 + 2.5 $\sqrt[]{3}$

F₂= mg sinq – f_K

= 25 – 2.5

F₁ – F₂ = 5 $\sqrt[]{3}$ N

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a week ago

Physics Laws of Motion Class 11th

A ball is projected from ground with initial momentum p at an angle q. What is the magnitude of net change in linear momentum when it reaches at maximum height of journey?

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