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Physics Motion in Straight Line

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2 weeks ago

Physics Motion in Straight Line Class 11th

An object is thrown vertically upwards. At its maximum height, which of the following quantity becomes zero?

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Raj Pandey

Contributor-Level 9

At maximum height velocity (v) = 0

So, momentum = mv = m * 0 = 0

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2 weeks ago

Physics Motion in Straight Line Class 11th

A small toy starts moving from the position of rest under a constant acceleration. If it travels a distance of 10m in t s, the distance travelled by the toy in the next t s will be:

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Vishal Baghel

Contributor-Level 10

According to question, we can write

10 = $\frac{1}{2} a t^{2} . . . . . . . . . . . . . . . (1) a n d$

$10 + x = \frac{1}{2} a {(2 t)}^{2} . . . . . . . . . . . . . . . . (2)$

$\Rightarrow X = \frac{1}{2} A [{(2 t)}^{2} - t^{2}] = 3 (\frac{1}{2} a t^{2}) = 30 m$

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2 weeks ago

Physics Motion in Straight Line Motion in a Straight Line

A small toy starts moving from the position of rest under a constant acceleration. If it travels a distance of 10m in t s, the distance travelled by the toy in the next t s will be:

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alok kumar singh

Contributor-Level 10

According to question, we can write

10 = $\frac{1}{2} a t^{2} . . . . . . . . . . . . . . . (1) a n d$

$10 + x = \frac{1}{2} a {(2 t)}^{2} . . . . . . . . . . . . . . . . (2)$

$\Rightarrow X = \frac{1}{2} A [{(2 t)}^{2} - t^{2}] = 3 (\frac{1}{2} a t^{2}) = 30 m$

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2 weeks ago

Physics Motion in Straight Line Class 11th

A goods train accelerating uniformly on a straight railway track, approaches an electric pole standing on the side of track. Its engine passes the pole with velocity $u$ and the guard's room passes with velocity $v$ . The middle wagon of the train passes the pole with a velocity

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Raj Pandey

Contributor-Level 9

Let S be the distance between Two ends a be the constant acceleration

As we know $v^{2} - u^{2} = 2 a S$

or, $a S = \frac{v^{2} - u^{2}}{2}$

Let $v_{c}$ be velocity at mid point.

Therefore, $v_{c}^{2} - u^{2} = 2 a \frac{S}{2}$

$v_{c}^{2} = u^{2} + a S$

$v_{c}^{2} = u^{2} + \frac{v^{2} - u^{2}}{2}$

$v_{c} = \sqrt[]{\frac{u^{2} + v^{2}}{2}}$

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2 weeks ago

Physics Motion in Straight Line Class 11th

An engine of a train, moving with uniform acceleration, passes the signal – post with velocity u and the last compartment with velocity $υ .$ The velocity with which middle point of the train passes the signal post is:

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Vishal Baghel

Contributor-Level 10

Assume the length of train be I and its acceleration be a.

$v^{2} = u^{2} + 2 a l \Rightarrow a l = \frac{v^{2} - u^{2}}{2}$

Velocity when middle point crosses the post,

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3 weeks ago

Physics Motion in Straight Line Class 11th

Two trains are approaching each other on the same track with velocity 100 km/h and 50 km/h. When they are at a distance of 300 km from each other, a bird starts flying from train 1 towards train 2. When the bird reaches train 2, it instantly reverses its direction and flies again towards train 1. This process continues till the bird is trapped between the trains when they collide. If the bird always travels at a constant speed 200 km/h, the total distance the bird flies is:

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Vishal Baghel

Contributor-Level 10

Time taken by trains to collide = 300/150 = 2hrs
Speed of bird = 200 km/hr
Total distance travelled by bird = 200 * 2 = 400 km

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3 weeks ago

Physics Motion in Straight Line Class 11th

If the velocity-time graph has the shape AMB, what would be the shape of the corresponding acceleration-time graph?

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alok kumar singh

Contributor-Level 10

For part AM, slope of v – t graph is constant but negative. For part MB, slope of v – t graph is constant but positive.

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3 weeks ago

Physics Motion in Straight Line Class 11th

A horizontal bridge is built across a river. A student standing on the bridge throws a small ball vertically upwards with a velocity $4 {m s}^{- 1}$ . The ball strikes the water surface after $4 s$ . The height of bridge above water surface is (Take $g =$ $10 {m s}^{- 2}$ ):

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Raj Pandey

Contributor-Level 9

Let height of bridge $= h$

Displacement of ball, $S = - h$

$\begin{array}{r} S = u t + \frac{1}{2} {a t}^{2} \\ - h = 4 * 4 + \frac{1}{2} (- 10) (4)^{2} \\ \Rightarrow h = 64 m \end{array}$

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3 weeks ago

Physics Motion in Straight Line Class 11th

A vehicle travels half the distance with speed V and the remaining distance with speed 2v. Its average speed is:

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Raj Pandey

Contributor-Level 9

Average speed $= (\frac{4 v^{2}}{3 v})$

$= \frac{4 v}{3}$

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3 weeks ago

Physics Motion in Straight Line Class 11th

The ratio of the distances travelled by a freely falling body in the $1^{st}, 2^{nd}, 3^{rd}$ and $4^{th}$ second:

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Raj Pandey

Contributor-Level 9

$\begin{array}{r} S_{nth} = u + \frac{a}{2} (2 n - 1) \\ S_{nth} \propto (2 n - 1) \\ = 1 : 3 : 5 : 7 \end{array}$

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