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Physics Motion in Straight Line

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Physics Motion in Straight Line Class 11th

A body when dropped freely from certain height, reaches the ground in time t second. The average velocity during its journey is

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alok kumar singh

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Physics Motion in Straight Line Class 11th

If number of divisions on circular scale is 50 in a screw gauge and pitch of screw is 1 mm then find least count of screw gauge.

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

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Physics Motion in Straight Line Class 11th

Distance travelled by a particle starting form rest and moving with an acceleration of 4/3 ms^-2, in the second is

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alok kumar singh

Contributor-Level 10

Graph with time must be parabola. At the highest point KE is zero

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Physics Motion in Straight Line Class 11th

If a particle starting from rest having constant acceleration covers distance S₁ in first (p – 1) seconds and S₂ in first p seconds, then determine time for which displacement is S₁ + S₂

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alok kumar singh

Contributor-Level 10

S₁ = $\frac{1}{2}$ a (p – 1)²

S₂ = $\frac{1}{2}$ ap²

S₁ + S₂ = $\frac{1}{2}$ a [ (p – 1)² + p²] = $\frac{1}{2}$ at²

$t = \sqrt[]{2 p^{2} + 1 - 2 p}$

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Physics Motion in Straight Line Class 11th

A particle is having uniform acceleration. If its displacement from t to (t + 1) second is 120 m and change in velocity is 50 m/s. Find its displacement (in m) in (t + 2) second.

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alok kumar singh

Contributor-Level 10

Dv = a (t + 1 – t)

a = 50 m/s²

$s = u + \frac{a}{2} (2 (t + 1) - 1)$

$120 = u + \frac{50}{2} (2 t + 1)$

u = 120 – 25 (2t +1)

In (t + 2)^th second

$s' = u + \frac{a}{2} (2 (t + 2) - 1)$

= u + 25 (2t + 3)

= 120 – 25 (2t) – 25 + 25 (2t) + 75

S' = 170 m

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Physics Motion in Straight Line Class 11th

A particle is moving in a straight line with velocity (v) = (t – 4) m/s. What is the average speed between t = 0 to t = 8 second?

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alok kumar singh

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Physics Motion in Straight Line Class 11th

A man who can swim with a speed of $2 k h / h$ wants to cross a river $200 m$ wide. If the river is flowing with a speed of $3 k m / h$ then in what minimum time can the man cross the river?