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Physics Moving Charges and Magnetism

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Physics Moving Charges and Magnetism Class 12th

A proton and a deuteron enter in a uniform magnetic field with equal kinetic energy in the direction perpendicular to the field. The ratio of radius of circular path is

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alok kumar singh

Contributor-Level 10

R = mv/qB = √2mk/qB

M_p/M_d= ½ and q_p/q_d =1/1

R_p/r_d = 1/√2

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Physics Moving Charges and Magnetism Class 12th

A proton, a deuteron and an a particle are moving with same momentum in a uniform magnetic field. The ratio of magnetic force acting on them is ----------- and their speed is ----------- in the ratio.

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Vishal Baghel

Contributor-Level 10

$v = \frac{p}{m} \Rightarrow v_{p} : v_{d} : v_{α} = 1 : \frac{1}{2} : \frac{1}{4} = 4 : 2 : 1$

$F_{m a g} = q v B \Rightarrow F_{P} : F_{d} : F_{α} = 1 * 4 : 1 * 2 : 2 * 1 = 2 : 1 : 1$

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Physics Moving Charges and Magnetism Class 12th

Magnetic fields at two points on the axis of a circular coil at a distance of 0.05m 0.2m from the centre are in the ratio 8 : 1. The radius of coil is-------------.

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Vishal Baghel

Contributor-Level 10

Magnetic field on the axis of a circular coil at distance x from centre, B = $\frac{μ_{0} N i r^{2}}{2 {(r^{2} + x^{2})}^{\frac{3}{2}}}$

$\frac{{(r^{2} + {(0.2)}^{2})}^{\frac{3}{2}}}{{(r^{2} + {(0.05)}^{2})}^{\frac{3}{2}}} = 8$ $\frac{r^{2} + {(0.2)}^{2}}{r^{2} + {(0.05)}^{2}} = 4 \Rightarrow r^{2} = 0.01 \Rightarrow r = 0.1 m .$

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Physics Moving Charges and Magnetism Class 12th

A proton and an alpha particle of the same velocity enter in a uniform magnetic field which is acting perpendicular to their direction of motion. The ratio of the radii of the circular paths described by the alpha particle and proton is:

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Raj Pandey

Contributor-Level 9

$r = \frac{m v}{q B}$

$r_{α} = \frac{m_{α} v}{q_{α} B}$

$r_{P} = \frac{m_{P} v}{q_{P} B}$

$\frac{r_{α}}{r_{P}} = \frac{m_{α} q_{P}}{m_{P} q_{α}} = \frac{m_{α}}{m_{P}} (\frac{q_{P}}{q_{α}})$

$= \frac{4 m}{m} (\frac{q}{2 q}) = 2 : 1$

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Physics Moving Charges and Magnetism Class 12th

Given below are two statements:

Statement I : The electric force changes the speed of the charged particle and hence charges its kinetic energy; whereas the magnetic force does not change like kinetic energy of the charged particle.

Statement II : The electric force accelerates the positively charged particle perpendicular to the direction of electric field. The magnetic force accelerated the moving charged particle along the direction of magnetic field.

In the light of the above statements, chose the most appropriate answer from the option given below:

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Vishal Baghel

Contributor-Level 10

According to Lorentz's Force, we can write

$\vec{F} = {\vec{F}}_{E l e c t r i c} + {\vec{F}}_{M a g n e t i c} = q \vec{E} + q (\vec{v} * \vec{B}), s o$

Statement I is correct but Statement II is incorrect

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Physics Moving Charges and Magnetism Class 12th

Two long current carrying conductors are placed parallel to each other at a distance of 8 cm between them. The magnitude of magnetic field produced at mid-point between the two conductors due to current flowing in them is 300 $μ T$ . the equal current flowing in the two conductors is:

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Vishal Baghel

Contributor-Level 10

If currents are flowing in same direction, magnetic field will cancel each other, so the currents must flowing in opposite direction

$B_{P} = \frac{μ_{0} I}{2 π r} * 2$

$\Rightarrow 300 * 1 0^{- 6} = \frac{4 π * 1 0^{- 7}}{2 π * 4 * 1 0^{- 2}} * 2$

=> I = 30 A

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Physics Moving Charges and Magnetism Class 12th

A singly ionized magnesium atom (A = 24) ion is accelerated to kinetic energy 5 ke V, and is projected perpendicularly into a magnetic field B of the magnitude 0.5 T. The radius of path formed will be ________cm.

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Raj Pandey

Contributor-Level 9

$r = \frac{m v}{q B} = \frac{\sqrt[]{2 k m}}{q B}$

$\frac{\sqrt[]{2 * 5 * 1 0^{3} * 1.6 * 1 0^{- 19} * 24 * 1.66 * 1 0^{- 27}}}{1.6 * 1 0^{- 19} * \frac{1}{2}}$

= 9.975 * 10^-2 cm

= 9.975 cm

$r \approx 10$ cm

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Physics Moving Charges and Magnetism Class 12th

An infinitely long hollow conducting cylinder with radius R carries a uniform current along its surface.

Choose the correct representation of magnetic field (B) as a function of radial distance (r) from the axis of cylinder.

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Raj Pandey

Contributor-Level 9

Using Ampere's law for long hollow cylinder carrying current on its surface

B_in = 0

$B_{o u t} = \frac{μ_{0} i}{2 π r}$

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New answer posted

a month ago

Physics Moving Charges and Magnetism Class 12th

Given below are two statements:

In the light of the above statements, chose the most appropriate answer from the option given below:

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alok kumar singh

Contributor-Level 10

According to Lorentz's Force, we can write

$\vec{F} = {\vec{F}}_{E l e c t r i c} + {\vec{F}}_{M a g n e t i c} = q \vec{E} + q (\vec{v} * \vec{B}), s o$

Statement I is correct but Statement II is incorrect

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New answer posted

a month ago

Physics Moving Charges and Magnetism Class 12th

Two long current carrying conductors are placed parallel to each other at a distance of 8 cm between them. The magnitude of magnetic field produced at mid-point between the two conductors due to current flowing in them is 300 $μ T$ . the equal current flowing in the two conductors is:

0 Follower 4 Views

alok kumar singh

Contributor-Level 10

If currents are flowing in same direction, magnetic field will cancel each other, so the currents must flowing in opposite direction

$B_{P} = \frac{μ_{0} I}{2 π r} * 2$

$\Rightarrow 300 * 1 0^{- 6} = \frac{4 π * 1 0^{- 7}}{2 π * 4 * 1 0^{- 2}} * 2$

$\Rightarrow$ I = 30 A

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