Physics Moving Charges and Magnetism

Get insights from 108 questions on Physics Moving Charges and Magnetism, answered by students, alumni, and experts. You may also ask and answer any question you like about Physics Moving Charges and Magnetism

108
Questions
0
Discussions
0
Active Users
0
Followers

Have a question about Physics Moving Charges and Magnetism? Ask our experts

Ask Your Question

Keep it short & simple. Type complete word. Avoid abusive language.

New answer posted•a year ago

Physics Moving Charges and Magnetism Class 12th

A proton and a deuteron enter in a uniform magnetic field with equal kinetic energy in the direction perpendicular to the field. The ratio of radius of circular path is

3 Views|Posted a year ago

Asked by Alok Kumar Singh

Answered by

Alok Kumar Singh | Contributor-Level 10

a year ago

R = mv/qB = √2mk/qB

M_p/M_d= ½ and q_p/q_d =1/1

R_p/r_d = 1/√2

Upvote

New answer posted•a year ago

Physics Moving Charges and Magnetism Class 12th

A proton, a deuteron and an a particle are moving with same momentum in a uniform magnetic field. The ratio of magnetic force acting on them is ----------- and their speed is ----------- in the ratio.

3 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

$v = \frac{p}{m} \Rightarrow v_{p} : v_{d} : v_{α} = 1 : \frac{1}{2} : \frac{1}{4} = 4 : 2 : 1$

$F_{m a g} = q v B \Rightarrow F_{P} : F_{d} : F_{α} = 1 \times 4 : 1 \times 2 : 2 \times 1 = 2 : 1 : 1$

Upvote

New answer posted•a year ago

Physics Moving Charges and Magnetism Class 12th

Magnetic fields at two points on the axis of a circular coil at a distance of 0.05m 0.2m from the centre are in the ratio 8 : 1. The radius of coil is-------------.

3 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

Magnetic field on the axis of a circular coil at distance x from centre, B = $\frac{μ_{0} N i r^{2}}{2 {(r^{2} + x^{2})}^{\frac{3}{2}}}$

$\frac{{(r^{2} + {(0.2)}^{2})}^{\frac{3}{2}}}{{(r^{2} + {(0.05)}^{2})}^{\frac{3}{2}}} = 8$ $\frac{r^{2} + {(0.2)}^{2}}{r^{2} + {(0.05)}^{2}} = 4 \Rightarrow r^{2} = 0.01 \Rightarrow r = 0.1 m .$

Upvote

New answer posted•a year ago

Physics Moving Charges and Magnetism Class 12th

A proton and an alpha particle of the same velocity enter in a uniform magnetic field which is acting perpendicular to their direction of motion. The ratio of the radii of the circular paths described by the alpha particle and proton is:

6 Views|Posted a year ago

Asked by Raj Pandey

Answered by

Raj Pandey | Contributor-Level 9

a year ago

$r = \frac{m v}{q B}$

$r_{α} = \frac{m_{α} v}{q_{α} B}$

$r_{P} = \frac{m_{P} v}{q_{P} B}$

$\frac{r_{α}}{r_{P}} = \frac{m_{α} q_{P}}{m_{P} q_{α}} = \frac{m_{α}}{m_{P}} (\frac{q_{P}}{q_{α}})$

$= \frac{4 m}{m} (\frac{q}{2 q}) = 2 : 1$

Upvote

New answer posted•a year ago

Physics Moving Charges and Magnetism Class 12th

Given below are two statements:

Statement I : The electric force changes the speed of the charged particle and hence charges its kinetic energy; whereas the magnetic force does not change like kinetic energy of the charged particle.

Statement II : The electric force accelerates the positively charged particle perpendicular to the direction of electric field. The magnetic force accelerated the moving charged particle along the direction of magnetic field.

In the light of the above statements, chose the most appropriate answer from the option given below:

5 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

According to Lorentz’s Force, we can write

$\vec{F} = {\vec{F}}_{E l e c t r i c} + {\vec{F}}_{M a g n e t i c} = q \vec{E} + q (\vec{v} \times \vec{B}), s o$

Statement I is correct but Statement II is incorrect

Upvote

New answer posted•a year ago

Physics Moving Charges and Magnetism Class 12th

Two long current carrying conductors are placed parallel to each other at a distance of 8 cm between them. The magnitude of magnetic field produced at mid-point between the two conductors due to current flowing in them is 300 $μ T$ . the equal current flowing in the two conductors is:

5 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

If currents are flowing in same direction, magnetic field will cancel each other, so the currents must flowing in opposite direction

$B_{P} = \frac{μ_{0} I}{2 π r} \times 2$

$\Rightarrow 300 \times 1 0^{- 6} = \frac{4 π \times 1 0^{- 7}}{2 π \times 4 \times 1 0^{- 2}} \times 2$ &n

Upvote

New answer posted•a year ago

Physics Moving Charges and Magnetism Class 12th

A singly ionized magnesium atom (A = 24) ion is accelerated to kinetic energy 5 ke V, and is projected perpendicularly into a magnetic field B of the magnitude 0.5 T. The radius of path formed will be ________cm.

4 Views|Posted a year ago

Asked by Raj Pandey

Answered by

Raj Pandey | Contributor-Level 9

a year ago

$r = \frac{m v}{q B} = \frac{\sqrt[]{2 k m}}{q B}$

$\frac{\sqrt[]{2 \times 5 \times 1 0^{3} \times 1.6 \times 1 0^{- 19} \times 24 \times 1.66 \times 1 0^{- 27}}}{1.6 \times 1 0^{- 19} \times \frac{1}{2}}$