Physics Moving Charges and Magnetism

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New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

B = μ 0 n i = μ 0 N l i

B = 4 π * 10 - 7 * 100 10 - 3 * 1 = 12.56 * 10 - 2 T

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

For resonance frequency

ω L = 1 ω C ω = 1 L C = 1 10 * 10 - 3 * 1 * 10 - 6 = 1 10 - 8 = 10 4 r a d / s e c f = ω 2 π = 10 4 2 π = 1.59 k H z

New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

d B ? = μ 0 ( I l ? l ? * r ? ) 4 π r 3

The expression for magnetic field depends on current carrying element I d ? l ?  , which is a vector quantity, therefore, statement-I is correct and statement-II is wrong.

New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

R = mv / (qB) = √ (2mK) / (qB) ⇒ K = (R²q²B²) / (2m)

⇒ K? /Kα = (R? ²q? ²B² / 2m? ) * (2mα / (Rα²qα²B²) = (mα/m? ) * (R? /Rα)² * (q? /qα)²

⇒ K? /Kα = (4) * (2)² * (1/2)² = 4:1

New answer posted

a month ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

In external magnetic field, a magnetic force acts on every small part of the loop in direction perpendicular to the wire. Thus, loop assumes a shape (circular) in which it covers maximum area

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a month ago

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alok kumar singh

Contributor-Level 10

The magnetic field B is calculated as:
B = 2 * (μ? I / 4πr) + (μ? I / 4πr) = (μ? I / 4πr) * (2 + π)

New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

B = μni

B = (500 * 4π * 10? ) * 1000 * 5

B = π Tesla

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

2 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

2 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

BA = μ?Iθ / 4πR
⇒ BA/BB = IAθARB / IBθBRA
⇒ (2(3π/2)(4)) / (3(π/3)(2))
⇒ 6/5

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