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Physics NCERT Exemplar Solutions Class 11th Chapter Fourteen

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4 months ago

Physics NCERT Exemplar Solutions Class 11th Chapter Fourteen Class 11th

A body of mass m is attached to one end of a massless spring which is suspended vertically from a fixed point. The mass is held in hand so that the spring is neither stretched nor compressed. Suddenly the support of the hand is removed. The lowest position attained by the mass during oscillation is 4cm below the point, where it was held in hand. (a) What is the amplitude of oscillation? (b) Find the frequency of oscillation?
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Physics NCERT Exemplar Solutions Class 11th Chapter Fourteen Class 11th

A person normally weighing 50 kg stands on a massless platform which oscillates up and down harmonically at a frequency of 2.0 s-1 and an amplitude 5.0 cm. A weighing machine on the platform gives the persons weight against time. (a) Will there be any change in weight of the body, during the oscillation? (b) If answer to part (a) is yes, what will be the maximum and minimum reading in the machine and at which position?
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Payal Gupta

Contributor-Level 10

This is a long answer type question as classified in NCERT Exemplar

(a) The weight of the body changes during oscillations.

(b) Considering the situations in two extreme positions

we can say mg-N= ma

so at the highest point the platform is accelerating downward.

N=mg-ma

a=w2A

N=mg-mw2A

A= amplitude of motion m=50kg v=2m/s

w=2 π v = 4 π r a d / s

 A= 5cm = 5 * 10 - 2 m

N= 50 * 9.8 - 50 * 4 π 2 * 5 * 10 - 2 = 95.5 N

When it is accelerating towards mean position that is vertically upwards

N-mg=ma=Mw2A

N=mg+mw2A

N=m (g+w2A)

N= 50 [9.8+ ( 4 π ) 2 * 5 * 10 - 2 ]

N= 884N

Machine reads the normal reaction

Maximum weight =884N

Minimum weight=95.5N

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