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Physics NCERT Exemplar Solutions Class 12th Chapter Eight

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4 months ago

Physics NCERT Exemplar Solutions Class 12th Chapter Eight Mechanical Properties of Solids

If the length of a wire is made double and radius is halved of its respective values. Then, the Young’s modulus of the material of wire will :

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4 months ago

Physics NCERT Exemplar Solutions Class 12th Chapter Eight Gravitation

A body is moving in a low circular orbit about a planet of mass $M$ and radius $R$ . The radius of the orbit can be taken to be $R$ itself. Then the ratio of the speed of this body in the orbit to the escape velocity from the planet is :

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alok kumar singh

Contributor-Level 10

Sol. $\overset{?}{U} = 5 \hat{j}$

$\overset{?}{a} = 10 \hat{i} + 4 \hat{j}$

$\Rightarrow \overset{?}{S} = \overset{?}{U} t + \frac{1}{2} (\overset{?}{a}) t^{2}$

$\Rightarrow 20 \hat{i} + y_{0} \hat{j} = (5 t^{2}) \hat{i} + (5 t + 2 t^{2}) \hat{j}$

$\begin{array}{r} 20 = 5 t^{2} y_{0} = 5 t + 2 t^{2} \\ t = 2 \Rightarrow 18 m . \end{array}$

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4 months ago

Physics NCERT Exemplar Solutions Class 12th Chapter Eight Electromagnetic Waves

The electric field of a plane electromagnetic wave is given by $\overset{?}{E} = E_{0} (\hat{x} + \hat{y}) s i n ? (k z - ω t)$ Its magnetic field will be given by:

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

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4 months ago

Physics NCERT Exemplar Solutions Class 12th Chapter Eight Semiconductor Electronics

The cut-off voltage of the diodes (shown in figure) in forward bias is 0.6 V. The current through the resister of 40 $Ω$ is………….mA

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Payal Gupta

Contributor-Level 10

D₁ → forward biased

D₂ → Reversed biased

So, current will flow through only D₁

$l = \frac{(1 - 0.6) v}{(60 + 40) Ω} = \frac{0.4}{100}$

= 4 * 10^-³ A

= 4mA

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4 months ago

Physics NCERT Exemplar Solutions Class 12th Chapter Eight Electromagnetic Induction

A metallic rod of length 20 cm is placed in North-South direction and is moved at a constant speed of 20 m/s towards East. The horizontal component of the Earth's magnetic field at that place is 4 * 10^-³ T and the angle of dip is 45°. The emf induced in the rod is………….mV.

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Payal Gupta

Contributor-Level 10

$t a n δ = \frac{B_{v}}{B_{h}}$

$B v = B_{h} t a n 45$

= 4 * 10^-³

emf induced in the rod is = $B_{v} v l$

$= 4 * 1 0^{- 3} * 20 * \frac{20}{100}$

$\begin{array}{l} = 16 * 1 0^{- 3} \\ = 16 m v \end{array}$

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4 months ago

Physics NCERT Exemplar Solutions Class 12th Chapter Eight Moving Charges and Magnetism

A deuteron and a proton moving with equal kinetic energy enter into to a uniform magnetic field at right angle to the field. If r_d and r_p are the radii of their circular paths respectively, then the ratio $\frac{r_{d}}{r_{p}}$ will be $\sqrt[]{x} : 1$ where x is……….

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Payal Gupta

Contributor-Level 10

r_d = (Radius of deuteron)

$= \frac{m_{d} v_{d}}{q_{d} B}$

$= \frac{\sqrt[]{2 m_{d} k . E}}{q_{d} B}$

$= \frac{\sqrt[]{2 m_{P}}}{\sqrt[]{m_{P}}} * \frac{q_{P}}{q_{d}}$ $[q_{P} = q_{d} = 1.6 * 1 0_{C}^{- 19}]$

$= \sqrt[]{2} : 1$

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4 months ago

Physics NCERT Exemplar Solutions Class 12th Chapter Eight Electrostatic Potential and Capacitance

A parallel plate capacitor is made up of stair like structure with a plate area A of each stair and that is connected with a wire of length b, as shown in the figure. The capacitance of the arrangement is $\frac{x}{15} \frac{\in_{0} A}{b},$ the value of x is……………

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Payal Gupta

Contributor-Level 10

$C_{1} = \frac{\in_{0} A}{5 b}$

$C_{2} = \frac{\in_{0} A}{3 b}$

$C_{3} = \frac{\in_{0} A}{b}$

$C_{e q} = C_{1} + C_{2} + C_{3}$

$= \frac{\in_{0} A}{b} [\frac{1}{5} + \frac{1}{3} + 1]$

$C_{e q} = \frac{23}{15} \frac{\in_{0} A}{b}$

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4 months ago

Physics NCERT Exemplar Solutions Class 12th Chapter Eight Oscillations

A particle executives simple harmonic motion. Its amplitude is 8cm and time period is 6s. The time it will take to travel from its position of maximum displacement to the point corresponding to half of its amplitude, is………… s.

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Payal Gupta

Contributor-Level 10

A = 8 cm

T = 6 sec

q = 60° from A to B

During reaching the point its maximum amplitude from point (A)

$θ = 60 ° = \frac{π^{C}}{3}$

$θ = ω t$

$\frac{π}{3} = \frac{2 π}{6} t$

t = 1 sec

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4 months ago

Physics NCERT Exemplar Solutions Class 12th Chapter Eight Thermodynamics

A diatomic gas $(γ = 1.4)$ does 400 J of work when it is expanded isobarically. The heat given to the gas in the process is…………….J.

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Payal Gupta

Contributor-Level 10

$w = P Δ v = n R Δ T = 400 J$ - (1)

$Q = n C_{P} Δ T = \frac{n R y}{y - 1} Δ T$

$Q = \frac{14}{4} * 400$

Q = 1400 J

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4 months ago

Physics NCERT Exemplar Solutions Class 12th Chapter Eight System of Particles and Rotational Motion

A rolling wheel of 12kg is on an inclined plane at position P and connected to a mass of 3kg through a string of fixed length and pulley as shown in figure.

Consider PR as friction free surface. The velocity of centre of mass of the wheel when it reaches at the bottom Q of the inclined plane PQ will be $\frac{1}{2} \sqrt[]{x g h} m / s .$ The value of x is…………

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Payal Gupta

Contributor-Level 10

By conservation of Energy

$m g h = \frac{1}{2} l_{P} ω^{2}$

3gh $= \frac{1}{2} (M R^{2} + M R^{2}) ω^{2}$

$3 g h = m v^{2}$

$v^{2} = \frac{3 g h}{12}$

$v = \frac{\sqrt[]{g h}}{2} = \frac{\sqrt[]{x g h}}{2}$

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