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Physics NCERT Exemplar Solutions Class 12th Chapter Five

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2 months ago

Physics NCERT Exemplar Solutions Class 12th Chapter Five Laws of Motion

A hanging mass M is connected to a four times bigger mass by using a string-pulley arrangement, as shown in the figure. The bigger mass is placed on a horizontal ice-slab and being pulled by 2 Mg force. In this situation, tension in the string is $\frac{x}{5} M g$ for x_________. Neglect mass of the string and fiction of the block (bigger mass) with ice slab.

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Payal Gupta

Contributor-Level 10

Using newton's law:

2mg – T = 4ma - (1)

T – mg = ma - (2)

From (1) & (2) :

$m g = 5 m a \Rightarrow a = \frac{g}{5} = 2 m / s^{2}$

$T = m g + \frac{m g}{5} = \frac{6 m g}{5}$

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2 months ago

Physics NCERT Exemplar Solutions Class 12th Chapter Five Laws of Motion

A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration (a) is varying with time t as a = k² rt², where k is a constant. The power delivered to the particle by the force acting on it is given as

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Payal Gupta

Contributor-Level 10

a = k²rt²

$\Rightarrow \frac{v^{2}}{r} = k^{2} r t^{2}$

$\Rightarrow v = k r t$

$a_{t} = \frac{d v}{d t} = k r$

⇒ tangential force, F_t = ma_t = mkr

$∴ P o w e r d e l i v e r e d, P = F_{t} v = (m k r) (k r t) = m k^{2} r^{2} t$

Note → Power delivered by centripetal force will be zero.

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3 months ago

Physics NCERT Exemplar Solutions Class 12th Chapter Five Laws of Motion

The time period of oscillation of a simple pendulum of length L suspended from the roof of a vehicle, which moves without friction down an inclined plane of inclination , is given by:

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Vishal Baghel

Contributor-Level 10

goff = g cos

$∴ T = 2 π \sqrt[]{\frac{L}{g c o s α}}$

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3 months ago

Physics NCERT Exemplar Solutions Class 12th Chapter Five Laws of Motion

A small ball of mass $m$ is thrown upward with velocity $u$ from the ground. The ball experiences a resistive force ${m k v}^{2}$ where $v$ is it speed. The maximum height attained by the ball is:

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alok kumar singh

Contributor-Level 10

Sol. Sol. ⇒ Electric field due to infinite sheet is uniform

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3 months ago

Physics NCERT Exemplar Solutions Class 12th Chapter Five Magnetism and Matter

A paramagnetic sample shows a net magnetisation of $6 A / m$ when it is placed in an external magnetic field of $0.4 T$ at a temperature of $4 K$ . When the sample is placed in an external magnetic field of $0.3 T$ at a temperature of $24 K$ , then the magnetisation will be :

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alok kumar singh

Contributor-Level 10

Sol. $ρ v g - m g = m a$

$\Rightarrow \frac{ρ v g}{m} = g + a$

$\Rightarrow m = \frac{ρ v g}{g + a}$

$\Rightarrow \frac{10^{3} (\frac{4}{3} π * 10^{- 6}) (9.8)}{9.898}$

$\Rightarrow 4.15 g m$

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3 months ago

Physics NCERT Exemplar Solutions Class 12th Chapter Five Laws of Motion

A mass of 10kg is suspended vertically by a rope of length 5m from the roof. A force of 30 N is applied at the middle point of rope in horizontal direction. The angle made by upper half of the rope with vertical is q = tan^-¹ (x * 10^-¹). The value of x is…………….

(Given, g = 10 m/s²)

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Payal Gupta

Contributor-Level 10

F.B.D. of point 'P'

$T s i n θ = 30$ - (1)

$T c o s θ = 100$ - (2)

$(1) \div (2)$

$t a n θ = \frac{3}{10} \Rightarrow θ = t a n^{- 1} (3 * 1 0^{- 1})$

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3 months ago

Physics NCERT Exemplar Solutions Class 12th Chapter Five Laws of Motion

One end of a massless spring of spring constant k and natural length $l_{0}$ is fixed while the other end is connected to a small object of mass m lying on a frictionless table. The spring remains horizontal on the table. If the object is made to rotate at an angular velocity $ω$ about an axis passing through fixed end, then the elongation of the spring will be

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Payal Gupta

Contributor-Level 10

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3 months ago

Physics NCERT Exemplar Solutions Class 12th Chapter Five NEET

What is magnetic susceptibility and how is it different for diamagnetic, paramagnetic, and ferromagnetic materials?

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Pallavi Pathak

Contributor-Level 10

Magnetic susceptibility (? ) measures in an external magnetic field, how much a material gets magnetized.Paramagnetic materials:? is positive but small.
Diamagnetic materials:? is negative and very small.
Ferromagnetic materials:? is positive and large, often many orders of magnitude greater than 1.

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3 months ago

Physics NCERT Exemplar Solutions Class 12th Chapter Five NEET

Why does a bar magnet suspended freely always point in the north-south direction?

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Pallavi Pathak

Contributor-Level 10

Any bar magnet which is freely suspended aligns itself with the Earth's magnetic field. Earth attract the north pole of the suspended magnet because earth behaves like a giant bar magnet with a magnetic south pole near the geographic North Pole.

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3 months ago

Physics NCERT Exemplar Solutions Class 12th Chapter Five NEET

What is the difference between magnetic intensity (H) and magnetic field (B)?

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Pallavi Pathak

Contributor-Level 10

The magnetizing force applied to a material is called the Magnetic intensity (H) and the total magnetic effect inside a material is called the magnetic field (B), it includes both the applied magnetic field and the material's response (magnetization).
Following is the formula showing the relation:
B =? (H + M)
Where? is the permeability of free space and M is magnetization.

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