physics ncert solutions class 11th
Get insights from 952 questions on physics ncert solutions class 11th, answered by students, alumni, and experts. You may also ask and answer any question you like about physics ncert solutions class 11th
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New answer posted
4 months agoContributor-Level 10
This is a multiple choice answer as classified in NCERT Exemplar
(c) As the body is falling freely under gravity, the potential energy decreases and kinetic energy increases but total mechanical energy (PE+KE) of the body and earth system will be constant as external force on the system is zero.
New answer posted
4 months agoContributor-Level 10
This is a multiple choice answer as classified in NCERT Exemplar
(c) Work done by the frictional force on the cycle and is equal to -200 =-2000J
As the road is not moving, hence work done by the cycle on the road = zero.
New answer posted
4 months agoContributor-Level 10
This is a multiple choice answer as classified in NCERT Exemplar
When the man is squatting on the ground he is tilted somewhat, hence he also has to balance frictional force besides his weight in this case.
R= reactional force = friction +mg
R>mg
New answer posted
4 months agoContributor-Level 10
This is a multiple choice answer as classified in NCERT Exemplar
(c) Force between two protons is same as that of between proton and a positron. As positron is much lighter than proton, it moves away through much larger distance compared to proton.
We know that work done = force (distance). As forces are same in case of proton and positron but distance moved by positron is larger, hence work will be more.
New answer posted
4 months agoContributor-Level 10
This is a multiple choice answer as classified in NCERT Exemplar
(b) When electron and proton are moving under influence of their mutual forces the magnetic forces will be perpendicular to their motion hence no work is done by these forces.
New answer posted
4 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
Energy given by 1 lit of petrol = 3
Efficiency of the car engine=0.5s
Energy used by the car = 0.5
Total distance travelled s = 15km = 15
If f the force of friction= E= f
1.5 = f
F=
F= 1000 N
New answer posted
4 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
Weight of the adult w= mg =600N
Height of each step = h = 0.25m
Total distance travelled = 6km =6000m
Total number of steps = 6000/1= 6000
Total energy utilised in jogging = n mgh
= 6000 600 0.25J
= 9 J
Since 10% of intake energy is utilised in jogging
So total energy intake = 10
New answer posted
4 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
Mass of the system = 50000kg
Speed of the system v= 36km/h= 10m/s
Compression of the spring x= 1m
KE of the system = 1/2mv2
= ½ (50000) (10)2
= 25000 (100)J= 2.5
Since 90 % of KE is lost due to the friction so energy transferred is
E= 1/2kx2= 10% of total KE of the system
= 0r K =
New answer posted
4 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
Mass of drop m = 3
Terminal velocity = 9m/s
Height = 100cm=1m
Density of water = 103kg/m3
Area of the surface = 1m2
Volume of the water due to rain V = area height
= 1 (1)= 1m3
Mas s of water due to rain M= volume (density)
= V ( )= 103kg
Energy transferred to the surface = 1/2mv2
New answer posted
4 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
At t=0 suppose bob B is displaced by angle 10 to the right . it is given potential energy E1=E . energy of A, E2=0
When B is released it strikes at A at t=T/4 in the head on elastic collision between B and A comes to rest and A gets velocity of B. therefore E1=0 and E2=E. at A =2T/4, B reaches its extreme right position when KE of A is converted into PE=E2=E . Energy of B, E1=0

At t=3T/4. A reaches its mean position when its PE is converted into KE =E2 =E. it collides elastically with B and transfers whole of its energy to B. thus E2=0 and E1 =E . the entire process is r
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 686k Reviews
- 1800k Answers


