Physics Ncert Solutions Class 12th
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New answer posted
4 months agoContributor-Level 10
This is a Long Answer Type Questions as classified in NCERT Exemplar
Explanation- iG (G) = (I1-IG) (S1+S2+S3) for I1= 10mA
iG (G+S1) = (I2-IG) (S2+S3) for I2= 100mA
iG (G+S1+S2) = (I3-IG) (S3) for I3= 1A
S1= 1W, S2= 0,1W and S3= 0.01W
New answer posted
4 months agoContributor-Level 10
This is a Long Answer Type Questions as classified in NCERT Exemplar
Explanation- B (z) points in the same direction on z-axis and hence, J (L) isa monotonically function of L so B.dl = B.dl as cos 0 = 1
(b) but when L
So B 1/r3
(c) the magnetic field due to a circular current carrying loop of radius in the xy plane with centre at origin at any point lying at a distance of from origin.

B=
Z=Rtan
dz=Rsec2
=
New question posted
4 months agoNew answer posted
4 months agoContributor-Level 10
This is a long answer type question as classified in NCERT Exemplar
Potential energy of system of charges be algebraic sum
U =
9 109/10-15 (1.6 -19)2 (1/3)2- (2/3) (1/3)- (2/3) (1/3)
-7.68 10-14J
-7.68 10-14 -19= 0.48Mev
New answer posted
4 months agoContributor-Level 10
This is a Long Answer Type Questions as classified in NCERT Exemplar
Explanation- B (z) points in the same direction on z-axis and hence, J (L) isa monotonically function of L so B.dl = B.dl as cos 0 = 1
(b) but when L
So B 1/r3
(c) the magnetic field due to a circular current carrying loop of radius in the xy plane with centre at origin at any point lying at a distance of from origin.

B=
Z=Rtan
dz=Rsec2
=
New answer posted
4 months agoContributor-Level 10
This is a Long Answer Type Questions as classified in NCERT Exemplar
Explanation- as we know magnetic moment = nIA
For equilateral triangle M= nIA= 4I ( )
M= Ia2
For square, n=3 so total length of wire is 12a
M= nIA= 3I (a2) = 3Ia2
For regular hexagon of side a, n=2 so total length = 12a
M= nIA=2 ( )= 3 a2I
New answer posted
4 months agoContributor-Level 10
This is a Long Answer Type Questions as classified in NCERT Exemplar
Explanation- Since, B is along the x-axis, for a circular orbit the momenta of the two particles are in the y-z plane. Let P1 and P2 be the momentum of the electron and positron, respectively. Both traverse a circle of radius R of opposite sense. Let P1 make an angle? with the y-axis P2 must make the same angle.

The centres of the respective circles must be perpendicular to the momenta and at a distance R. Let the centre of the electron be at Ce and of the positron at Cp . The coordinates of Ce is
Ce= (0, -Rsin )
Cp= (0, -Rsin )
The circles of the two
New answer posted
4 months agoContributor-Level 10
This is a Long Answer Type Questions as classified in NCERT Exemplar
Explanation- the thicker wire has a resistance R, then the other wire has a resistance @R as the wires are of the same material but different area


New answer posted
4 months agoContributor-Level 10
This is a Long Answer Type Questions as classified in NCERT Exemplar
Explanation – for equilibrium balance net torque should be zero
Mgl= Wcoill
500gl = Wcoill
Wcoil= 500 9.8N
Taking moment of force about mid point then magnetic field
Mgl+mgl=Wcoill+IBlsin90
Mgl=BILl
M= -3kg= 1g
New question posted
4 months agoTaking an Exam? Selecting a College?
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