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New answer posted

4 months ago

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V
Vishal Baghel

Contributor-Level 10

Gold band is equal to 5% tolerance

New answer posted

4 months ago

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V
Vishal Baghel

Contributor-Level 10

t? , half life = (log?2)/λ = 3 s
Initially 200 nuclei were there
After 3 half-lives, 9 seconds,
No. of nuclei = (1/2³) (200) = 25
Therefore, the number of nuclei that decayed = 200 – 25 = 175

New answer posted

4 months ago

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V
Vishal Baghel

Contributor-Level 10

EMF induced = BLV = 4 * 2 * 1 = 8V
Current produced = BLV/R = 8/1 = 8A

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4 months ago

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V
Vishal Baghel

Contributor-Level 10

x = 8R/2 ; y = 5R/2 ; x/y = 8/5 = 1.6

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4 months ago

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Vishal Baghel

Contributor-Level 10

When relative sliding stops, both move with same velocity.
Only friction acts in horizontal direction.
∴ for system no external force, we can apply conservation of momentum.
1 * 12 + 5 * 0 = 6 * v
v = 2 m/s
Now work done by friction on block = change in kinetic energy of block
w = (1/2)m (2² - 12²) = (1/2) (1) (4 - 144) = (1/2) (-140) = -70 J

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4 months ago

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V
Vishal Baghel

Contributor-Level 10

Charge initially on capacitor 1=10µC
Charge initially on capacitor 2=20µC
Finally the potential difference across both capacitor will be equal.
Let us assume that to be V.
1V + 2V = +10
V = 10 / 3 = 3.33V

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4 months ago

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Vishal Baghel

Contributor-Level 10

In case 1, E? = 2eV; φ? ? = E? - KE? = 1eV
In case 2, E? = 12400/1550 = 8eV; max.KE = 8eV - 1eV = 7eV

New answer posted

4 months ago

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V
Vishal Baghel

Contributor-Level 10

Using parallel axis theorem for the side BC, the moment of inertia of the triangle about an axis passing through A and perpendicular to the plane of the triangle,
I? = 2 [ (1/3)ma²] + [ (1/12)ma² + m (√3a/2)²] = (3/2)ma²
If the angular velocity of the triangle at any instant is ω, the velocity of the vertex B at that instant is aω
Therefore, the velocity of B is maximum at the instant the angular velocity is maximum, i.e. when the side BC becomes horizontal
Let the angular velocity at this instant be ω?
Then, by conservation of energy
Gain in kinetic energy = Loss in potential energy
(1/2)I? ω²? = 3mg (Loss in height of CM of tr

...more

New answer posted

4 months ago

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V
Vishal Baghel

Contributor-Level 10

Centripetal acceleration is provided by friction force. Maximum friction force should be equal to or greater that mv² / R.
µmg = mv²/R ; µ = 100/ (100*10) ; µ = 1/10 ; µ = 0.1

New answer posted

4 months ago

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V
Vishal Baghel

Contributor-Level 10

Pitch p = 0.5 mm
Device has +ve zero error
R = 6p + 28p/50 - 4p/50 = 6p + 24p/50; 3mm + (24/50) * 0.5 = 3.24 mm

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