Physics
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New answer posted
7 months agoContributor-Level 10
µ = A? /A? = 0.5 {A? = 20 volt, A? = 40 volt}
m (t) = A? sin ω? t {ω? = 2π*10? }
c (t) = A? sin ω? t {ω? = 2π*10*10³}
C? (t) = (A? + A? sin ω? t) sin ω? t ⇒ A? {1+ µsin ω? t} sin ω? t
New answer posted
7 months agoContributor-Level 10
(hc/λ) = 13.6Z² (1/1² - 1/4²) = 13.6Z² (3/4) ; [λ = (4/3)k]
β line of Paschen
(hc/λ') = 13.6Z² (1/9 - 1/25)
λ = k * (9*25/16) ; λ' = (3/4)λ * (9*25/16) = (3³*5²/2? )λ
New answer posted
7 months agoContributor-Level 10
Applying conservation of momentum, m (ui + 2uj) + 3m (0) = 4m (vi +vj)
⇒ v = u / 4 and v' = u / 2
New answer posted
7 months agoContributor-Level 10
F = ηAdv / dx
η = F (dx/dv) (1/A) = m * a * time * (1/area) = MV/A
New answer posted
7 months agoContributor-Level 10
Note : As the incident light is unpolarized, intensity of emerging light does not depend on the polarization axis of polarizer.
New answer posted
7 months agoContributor-Level 10
Using conversation of momentum in direction perpendicular to the original direction of motion,
mv1 sin 30° = mv2 sin 30°

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