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New answer posted

11 months ago

0 Follower 39 Views

A
alok kumar singh

Contributor-Level 10

Maximum energy = 10 J

1 2 K x 2 = 1 0              

K = 5

Given Tpendulum = Tspring

2 π l g = 2 π m K             

4 g = 5 5           

g = 4m/s2

New answer posted

11 months ago

0 Follower 11 Views

V
Vishal Baghel

Contributor-Level 10

X c = 1 ω c , X L = ω L so at very high frequencies capacitor behaves as conduct and inductor behaves as open circuit. The effective impedance will be 2 Ω .

 

New answer posted

11 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

Distance of 4th bright fringe from central maxima = 4 λ D d  

S o , 2 . 4 1 0 0 = 8 λ D d λ = 2 . 4 * 0 . 3 * 1 0 3 1 0 0 * 8 * 1 . 5 = 6 * 1 0 7 m

f = c λ = 3 * 1 0 8 6 * 1 0 7 = 5 * 1 0 1 4 H z

New answer posted

11 months ago

0 Follower 21 Views

V
Vishal Baghel

Contributor-Level 10

Δ M M = Δ μ μ = 2 5 0 5 0 0 = 1 2

New answer posted

11 months ago

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V
Vishal Baghel

Contributor-Level 10

Signal bandwidth = 12KHz

No. of station = 6 M H z 1 2 k H z = 5 0 0

New answer posted

11 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Using Heat equation : H = i2Rt

=>192 = (4)2 R (1)

H = (8)2 R (5)

=>H = 3840 J

New answer posted

11 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

From question :

9MSD = 10VSD

LC = 1MSD – 1VSD = 1MSD - 9 1 0 M S D = 0 . 1 M S D = 0 . 1 * 1 m m = 0 . 1 m m

Reading = 10mm + 8 * 0.1 mm = 10.8 mm

Final reading = 10.8 mm – 0.04 mm = 10.4 mm = 104 * 10-2 cm

So radius = 52 * 10-2 cm

New answer posted

11 months ago

0 Follower 14 Views

V
Vishal Baghel

Contributor-Level 10

Equation from the given graph:

v 2 = 2 x + 2 0 v 2 = 2 x + 2 0 2 V d V d t = 2 V

=>a = 1m/s2

New answer posted

11 months ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

Range R = u 2 s i n 2 θ g

For 42° and 48° Range will be same

H m a x α  maximum q

So maximum height will be for 48°

 

New answer posted

11 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

When electric field is parallel then it would provide zero flux.

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