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New answer posted

11 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

Energy of electron in first existed state will be -3.4 eV.

So total energy difference will be (2.6 + 3.4) eV.

Wavelength ( λ ) = 1 2 4 2 e V n m 6 e V = 2 0 7 n m

F r e q u e n c y = c λ = 3 * 1 0 8 2 0 7 * 1 0 9 = 1 . 4 5 * 1 0 9 M H z

 

New answer posted

11 months ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

De Broglie wavelength

λ = h m V = h 2 m E E K . E .              

E = 3 2  KT for gas

S o λ = h 3 m K T = 6 . 6 * 1 0 3 4 3 * 9 * 1 0 3 1 * 1 . 3 8 * 1 0 2 3 * 3 0 0

λ = 6 . 2 6 * 1 0 9 m λ = 6 . 2 6 n m                

             

New answer posted

11 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

For equilibrium net force acting on the system should be zero.

New answer posted

11 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Using Ideal gas Equation :

PV = nRT

n = P V R T = 4 0 0 * 1 0 3 * 5 0 0 * 1 0 6 8 . 3 * 1 0 0 = 0 . 0 0 8    

=> m 1 = 0 . 1 2 , m 2 = 0 . 6 4

=> m 2 m 1 = 1 6 3

New answer posted

11 months ago

0 Follower 13 Views

V
Vishal Baghel

Contributor-Level 10

Force on q1 :

F q 1 = q ( V * B ) = 4 π ( 0 . 5 c i ^ ) * B 0 2 ( c o s ( k z ω t ) i ^ + c o s ( k z w t ) j ^ )

= 4 π ( 0 . 5 c ) ( B 0 2 ) c o s ( k π k ) k ^      

For on q2:

= 2 π ( 0 . 5 c ) ( B 0 2 ) c o s ( k 3 π k ) k ^

So ratio will be 2 : 1

New answer posted

11 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

For circular motion Fnet   = M V 2 R

2 F + F ' = M V 2 R

2 G M M ( 2 R ) 2 + G M M ( 2 R ) 2 = M V 2 R                

G M R [ 1 2 + 1 4 ] = V 2              

V = 1 2 G M R ( 2 2 + 1 )

 

New answer posted

11 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

Using F = MA = m V T  

=> m = FTV-1

 

New answer posted

11 months ago

0 Follower 18 Views

A
alok kumar singh

Contributor-Level 10

Magnetization (M) is directly proportional to magnetizing field and magnetic susceptibility does not depend on temperature so option 3 is correct.

New answer posted

11 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

Load of mass will be equally distributed among the four colours so force on each columns will be 125 * 103 N.

Cross section area of the column = π [ ( 1 ) 2 ( 0 . 5 ) 2 ] = 2 . 3 5 5 m 2

Using young's modulus :  ε = σ Y = F A Y = 1 2 5 * 1 0 3 2 . 3 5 5 * 2 * 1 0 1 1 = 2 . 6 5 * 1 0 7

New answer posted

11 months ago

0 Follower 23 Views

V
Vishal Baghel

Contributor-Level 10

Using truth table

A            B            V0

0            0

0            1            1

1            0            1

1            1

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