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Physics Class 12th

An unpolarised light beam of intensity 2l₀ is passed through a polaroid P and then through another polaroid Q which is oriented is such a way that its passing axis makes an angle of 30° relative to that of P. The intensity of the emergent light is

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Payal Gupta

Contributor-Level 10

$I = I_{0} c o s^{2} 30 °$

$= I_{0} {(\frac{\sqrt[]{3}}{2})}^{2} = \frac{3}{4} I_{0}$

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a year ago

Physics Class 11th

What is the application of elastic deformation?

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Syed Aquib Ur Rahman

Contributor-Level 10

Elastic deformation leads to the temporary change in a material's shape that is also reversible. It occurs for energy storage in devices, such as springs. It's also essential for understanding the flexibility of structural components like beams in bridges. This principle is used in engineering design. You can think vehicle suspension systems and even the resilience of buildings against wind forces.

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Physics Class 12th

A circuit element X when connected to an a.c. supply of peak voltage 100V given a peak current of 5A which is in phase with the voltage. A second element Y when connected to the same a.c. supply also gives the same value of peak current which lags behind the voltage by $\frac{π}{2} .$ If X and Y are connected in series to the same supply, what will be the rms value of the current in ampere?

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Payal Gupta

Contributor-Level 10

v = 100 sin $ω t$

$i_{0} = \frac{100}{R_{x}} = 5 \Rightarrow R_{x} = 20 Ω$

i = $5 s i n (ω t - \frac{π}{2})$

i = 100 5sin $ω t$

$5 = \frac{100}{R_{y}} \Rightarrow R_{y} = \frac{100}{5} = 20 Ω$

When x and y both are connected in series :-

v = 100sin $ω t$

tan = 1 = 45°

R₀ = $\sqrt[]{R_{x}^{2} + R_{y}^{2}} = 20 \sqrt[]{2} Ω$

$∴ \overset{o}{l_{0}} = \frac{v_{0}}{R_{0}} = \frac{100}{20 \sqrt[]{2}} = \frac{5}{\sqrt[]{2}} A .$

$∴ l_{m s} = \frac{l_{0}}{\sqrt[]{2}}$

$= \frac{5}{\sqrt[]{2} \cdot \sqrt[]{2}}$

$= \frac{5}{2} A = \frac{5}{2} A$

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a year ago

Physics Physics Motion in Straight Line

A juggler throws ball vertically upwards with same initial velocity in air. When the first ball reaches its highest positions he throws the next ball. Assuming the juggler throws n balls per second, the maximum height the balls can reach is

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Payal Gupta

Contributor-Level 10

Time to reach at max height t = $\frac{u}{g} n o .$ of balls thrown in 1 sec = n.

So, time taken by each ball to reach maxm height, = $\frac{1}{n} s e c$

i.e. $\frac{u}{g} = \frac{1}{n} \Rightarrow u = \frac{g}{n}$ So, hmax = $\frac{u^{2}}{2 g}$

= $\frac{g^{2}}{2 g n^{2}}$

$= \frac{g}{2 n^{2}}$

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a year ago

Physics Physics Moving Charges and Magnetism

A wire X of length 50cm carrying a current of 2A is placed parallel to a long wire Y of length 5m. The wire Y current of 3A. The distance between two wires is 5cm and currents flow in the same direction. The force acting on the wire Y is

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Payal Gupta

Contributor-Level 10

F_x-y = $\frac{μ_{0} i_{1} i_{2}}{2 π r} * (. 5)$

$= \frac{2 * 1 0^{- 7} * 6 * 0.5}{0.05}$

$= \frac{6}{5} * 1 0^{- 5} N = 1.2 * 1 0^{- 5}$

Force on Y = 1.2 * 105N towards 'x'

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a year ago

Physics Class 11th

What are some examples of elastic materials?

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Syed Aquib Ur Rahman

Contributor-Level 10

When we talk about elastic materials, we're referring to those that really show off their elasticity. Think of natural rubber, synthetic polymers, including spandex (also known as Lycra) and nylon, and even metals such as spring steel when they're within their elastic limits. These materials are quite resilient. They can store potential energy and bounce back to their original shape after being stretched or compressed. This behaviour is determined by the Hooke's Law.

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a year ago

Physics Class 11th

What are the applications of elastic energy?

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Syed Aquib Ur Rahman

Contributor-Level 10

Elastic energy is stored in objects that can deform. They have several applications, including springs in vehicle suspension systems and wind-up clocks. This potential energy, present in items like stretched rubber bands, trampolines, and an archer's bow, is converted to kinetic energy upon release.

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a year ago

Physics Class 12th

A 1m long wire is broken into two unequal parts X and Y. The X part of the wire is stretched into another wire W. Length of W is twice the length of X and the resistance of W is twice that of Y. Find the ratio of length of X and Y.

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Payal Gupta

Contributor-Level 10

R_w = 2R_y

$\Rightarrow ρ (\frac{2 x}{\frac{A}{2}}) = \frac{2 ρ (1 - x)}{A}$

$\frac{4 ρ x}{A} = \frac{2 ρ (1 - x)}{A}$

4x = 2 – 2x 6x = 2

x = $\frac{2}{6} = \frac{1}{3}$ $∴ \frac{L_{x}}{L_{y}} = \frac{\frac{1}{3}}{1 - \frac{1}{3}} = \frac{1}{3} * \frac{3}{2}$

$= \frac{1}{2}$

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a year ago

Physics Class 12th

Given below are two statements: one is labeled as Assertion A and the other is labeled as Reason R.

Assertion A : Alloys such as constantan and manganin are used in making standard resistance coils.

Reason R : Constantan and maganin have very small value of temperature coefficient of resistance.

In the light of the above statements, choose the correct answer from the options given below.

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Payal Gupta

Contributor-Level 10

Based on theoretical data.

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New answer posted

a year ago

Physics Class 12th

Two identical thin metal plates has charge q₁ and q₂ respectively such that q₁ > q₂. The plates were brought close to each other to from a parallel plate capacitor of capacitance C. The potential difference between them is

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Payal Gupta

Contributor-Level 10

V = $\frac{q_{(c a p a c i t a n c e)}}{C} = \frac{q_{1} - q_{2}}{2 c}$

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