Wave Optics

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New answer posted•a year ago
S
a year ago

The angle between the plane of vibration and plane of polarization is 90°.

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New answer posted•a year ago
S
a year ago

At lower end
Tension, T? = 2g = 20 N (due to the 2 kg block)
Velocity, v? = √ (T? /μ) = √ (20/μ)
Wavelength, λ? = 6 cm

At upper end
Tension, T? = (2 kg + 6 kg)g = 8g = 80 N (due to the block and the rope)
Velocity, v? = √ (T? /μ) = √ (80/μ) = √4 * √ (20/μ) = 2v?

Since frequency (f) remains the same:
f = v?

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New answer posted•a year ago
S
a year ago

β = λD / (d? + a? sinωt)
β? - β? = λD/ (d? - a? ) - λD/ (d? + a? )
= λD [ (d? + a? ) - (d? - a? ) / (d? ² - a? ²) ]
= 2λDa? / (d? ² - a? ²)

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New answer posted•a year ago
New answer posted•a year ago
S
a year ago

3d = 0.6mm

D = 80cm

= 800mm

Path difference is given by

BP – Andhra Pradesh = Dx

⇒ d y D = ( 2 n + 1 ) λ 2   [for Dark fringe at P]

n = 0, for first dark fringe

d y D = λ 2

λ = 2 d D y

= 2 d D × d 2                                     [ y = d 2 ,   G i v e n  first dark fringe is observed on the screen directly opposite to one of the slits]

λ = 2 × 0 . 6 × 0 . 6 8 0 0 × 2

λ = 4 5 0 m m

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New answer posted•a year ago
S
a year ago

  Energy     Volume   = M L 2 T - 2 L 3 = M L - 1 T - 2

 The distance between two successive bright fringes is fringe width ( β ) .

β = λ D d = 589 × 10 - 9 × 1.5 0.15 × 10 - 3 = 5.9 m m

 

 

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New answer posted•a year ago
S
a year ago

In primary rainbow, red colour is at top and violet is at bottom.

Intensity of secondary rainbow is less in comparison to primary rainbow.

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New answer posted•a year ago
S
a year ago

I A = 9 l + 4 l + 2 9 l × 4 l c o s 0 °

= 1 3 l + 1 2 l = 2 5 l

I B = 9 l + 4 l + 2 9 l × 4 l c o s π

= 1 3 l − 1 2 l = l

∴ I A − I B = 2 4 l

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