Physics

Given I = 2r

${\mu }_1=1\left(Air\right)$

${\mu }_2=\sqrt[]{2n}$

by, Snell's law

$\mu sini={\mu }_{2}sinr$

$i=2co{s}^{-1}\left[\sqrt[]{\frac{n}{2}}\right]$

$V_0=\frac{1}{5}C$

$V_0=\frac{C}{5},V_S=0$

$f=f_0\left[\frac{C+V_0}{C+V_s}\right]$

V0 observer velocity

C sound velocity

Vs source velocity

$=\frac{\frac{6}{5}{f}_0-f_0}{f_0}*100$

$=\frac{1}{5}*100$

% change in frequency = 20%

$x=Asin\omega t$

Angle travelled by while moving from A to B

$\theta =30°=\frac{\pi °}{6}$

$\theta =\omega t$

$\frac{\pi }{6}=\omega *3\left[t=3sec\right]$

$\omega =\frac{\pi }{18}$

$\Rightarrow T=\frac{2\pi }{\omega }=\frac{2\pi *18}{\pi }=36sec$

T = 36 sec

$F=qE\left[E=\frac{\sigma }{{\epsilon }_0}\right]$

$F=\frac{q\sigma }{{\in }_0}=10N$

Final case – Now one plate is removed, Electric field will becomes half; So, force will become half.

$F\text{'}=\frac{10}{2}=5N$

$\lambda =\frac{h}{mv}=\frac{h}{\sqrt[]{2MK.E}}$

$\lambda \alpha \frac{1}{\sqrt[]{m}}$

$\Rightarrow {\lambda }_{\alpha }\sqrt[]{m_{\alpha }}={\lambda }_{C_{12}}\sqrt[]{m_{C_{12}}}$

$\Rightarrow \frac{{\lambda }_{\alpha }}{{\lambda }_{C_{12}}}=\sqrt[]{\frac{m_{C_{12}}}{m_{\alpha }}}=\sqrt[]{\frac{12}{4}}=\sqrt[]{3}:1$

Ultraviolet rays – sterilizing surgical instrument

Microwaves – Radar system

Infrared waves – Greenhouse effect

X-rays – Study crystal structure

Given, I = 5 sin (120πt), $\omega$ $$ = 120

$T=\frac{2\pi }{\omega }$

$T=\frac{2\pi }{120\pi }=\frac{1}{60}sec,\frac{T}{4}=\frac{1}{60*4}=\frac{1}{240}sec$

Given, x = 99

${\mu }_0=4\pi *10^{-7}Wb/A-m$

${}_{}$ ${\mu }_m=?$   (Permeability of the material)

${\mu }_m=4\pi *10^{-5}$

mg = pvg

mg = d₁vg           ……. (i)

F_b = weight of fluid displaced = d₂vg         …… (ii)

by NLM 1            F_b + F_v = mg

F_V = mg - F_b

$F_v=mg\left(1-\frac{d_2}{d_1}\right)$

Com (Conservation of Momentum)

Pi = Pf

$\Rightarrow m{u}_1+5m{u}_2=m{v}_1+5m{v}_2$

$\Rightarrow m{u}_1=m{v}_1+5m{v}_2$

${}_{}$ $\Rightarrow u_1+v_1+5v_2$  …….(i)

& $e=1=\frac{v_2-v_1}{U_1-U_2}=\frac{v_2-v_1}{u_1}$ $\frac{{}_{}{}_{}}{{}_{}{}_{}}\frac{{}_{}{}_{}}{{}_{}}$

${}_{}{}_{}{}_{}$  $\Rightarrow u_1=v_2-v_1$ …….(ii)

Equation (i) + (ii)

$k.E_T=\frac{5}{9}{\left(K.E\right)}_i=55.6\mathrm{\%}$