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New answer posted

11 months ago

0 Follower 10 Views

A
alok kumar singh

Contributor-Level 10

Relaxation time ( τ ) V T

and T 1 V γ - 1

τ V 1 + γ - 1 2 τ V 1 + γ 2 τ f τ i = 2 V V 1 + γ 2 τ f τ i = ( 2 ) 1 + γ 2

New answer posted

11 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Electric field at t = 0 & ( x , y , z ) = 0,0 , π k  is

E ? = - i ˆ + j ˆ 2 E 0   and   F ? = E ? q F ? = - i ˆ + j ˆ 2 q

Which is antiparallel to i ˆ + j ˆ 2

New answer posted

11 months ago

0 Follower 9 Views

A
alok kumar singh

Contributor-Level 10

T 2 = 100 T 2 = F

F = 100 N

New answer posted

11 months ago

0 Follower 2 Views

S
Syed Aquib Ur Rahman

Contributor-Level 10

The period T is the time taken to complete one full revolution (2? radians). In uniform circular motion, it relates to angular velocity by? =2? /T and to tangential speed by v=? r=2? r/T .

New answer posted

11 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Using equation of continuity

A 1 V 1 = A 2 V 2 V 1 V 2 = A 2 A 1 = d 2 d 1 2 = 4.8 6.4 2 = 9 16

New answer posted

11 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

A = A 0 e - λ t

500 = 700 e - λ t λ t = l n ? 7 5 l n ? 2 t 1 / 2 * 30 = l n ? 7 5 ? t 1 / 2 = l n ? 2 * 30 l n ? 7 5

t 1 / 2 = 61.8 m i n 62 m i n

New answer posted

11 months ago

0 Follower 15 Views

A
alok kumar singh

Contributor-Level 10


x = retentivity

y = coercivity

z = saturation magnetization

New answer posted

11 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

  Energy     Volume   = M L 2 T - 2 L 3 = M L - 1 T - 2

 The distance between two successive bright fringes is fringe width ( β ) .

β = λ D d = 589 * 10 - 9 * 1.5 0.15 * 10 - 3 = 5.9 m m

 

 

New answer posted

11 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Magnetic energy per unit volume = B 2 2 ? 0

 

New answer posted

11 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

W equator   = W pole   - m ω 2 R

= 196 - 19.6 * 2 π 24 * 60 * 60 2 * 6400 * 10 3 = 195.33 N

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