Physics

Get insights from 5.6k questions on Physics, answered by students, alumni, and experts. You may also ask and answer any question you like about Physics

Follow Ask Question
5.6k

Questions

0

Discussions

28

Active Users

0

Followers

New answer posted

a year ago

0 Follower 10 Views

A
alok kumar singh

Contributor-Level 10

This is a Long Answer Type Questions as classified in NCERT Exemplar

Explanation- (a) Suppose the five wires A, B, C, D and E be perpendicular to the plane of paper at locations as shown in figure.

Thus, magnetic field induction due to five wires will be represented by various sides of a

closed pentagon in one order, lying in the plane of paper. So, its value is zero.

(b) Since, the vector sum of magnetic field produced by each wire at O is equal to 0.

Therefore, magnetic induction produced by one current carrying wire is equal in

magnitude of resultant of four wires and opposite in direction.

Therefore, the field if current in one of the wi

...more

New answer posted

a year ago

0 Follower 8 Views

P
Payal Gupta

Contributor-Level 10

This is a long answer type question as classified in NCERT Exemplar

As we know that,   σ =charge/Area

Q1= σ (4 π r 2)

Q2= σ (4 π ( 2 r ) 2)= 4Q1

when they come in contact with each other potential being same and charge will be conserved.

So net charge is 5Q1= 5 ( σ (4 π r 2)

Also V1=V2

KQ1/R=KQ2/2R  so Q1=Q2/2

Q1= 5 3 ( σ (4 π r 2) and Q2= 10 3 ( σ (4 π r 2)

σ =5 σ /3  and σ  =5 σ /6

New answer posted

a year ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

This is a Long Answer Type Questions as classified in NCERT Exemplar

Explanation- iG (G) = (I1-IG) (S1+S2+S3) for I1= 10mA

iG (G+S1) = (I2-IG) (S2+S3) for I2= 100mA

iG (G+S1+S2) = (I3-IG) (S3) for I3= 1A

S1= 1W, S2= 0,1W and S3= 0.01W

New answer posted

a year ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

This is a Long Answer Type Questions as classified in NCERT Exemplar

Explanation- B (z) points in the same direction on z-axis and hence, J (L) isa monotonically function of L so B.dl = B.dl as cos 0 = 1

(b) B.dl=μoI but when L  

So B  1/r3

(c) the magnetic field due to a circular current carrying loop of radius in the xy plane with centre at origin at any point lying at a distance of from origin.

 

B= μ0IR22 (Z2+R2)3/2

Z=Rtan θ

dz=Rsec2 θdθ

-Bzdz=μ0I2-π/2π/2cosθdθ = μ0I

New question posted

a year ago

0 Follower 1 View

New answer posted

a year ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

This is a long answer type question as classified in NCERT Exemplar

Potential energy of system of charges be algebraic sum

U = 1 4 π ? ? ( q q r - q q r - q q r )

9 * 109/10-15 (1.6 * 10 -19)2 (1/3)2- (2/3) (1/3)- (2/3) (1/3)

-7.68 * 10-14J

-7.68 * 10-14 * 1.6 * 10 -19= 0.48Mev

New answer posted

a year ago

0 Follower 10 Views

A
alok kumar singh

Contributor-Level 10

This is a Long Answer Type Questions as classified in NCERT Exemplar

Explanation- B (z) points in the same direction on z-axis and hence, J (L) isa monotonically function of L so B.dl = B.dl as cos 0 = 1

(b) B.dl=μoI but when L  

So B  1/r3

(c) the magnetic field due to a circular current carrying loop of radius in the xy plane with centre at origin at any point lying at a distance of from origin.

 

B= μ0IR22 (Z2+R2)3/2

Z=Rtan θ

dz=Rsec2 θdθ

-Bzdz=μ0I2-π/2π/2cosθdθ = μ0I

New answer posted

a year ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

This is a Long Answer Type Questions as classified in NCERT Exemplar

Explanation- as we know magnetic moment = nIA

For equilateral triangle M= nIA= 4I ( 34a2 )

M= Ia23

For square, n=3 so total length of wire is 12a

M= nIA= 3I (a2) = 3Ia2

For regular hexagon of side a, n=2 so total length = 12a

M= nIA=2 ( 634a2 )= 3 3 a2I

New answer posted

a year ago

0 Follower 11 Views

A
alok kumar singh

Contributor-Level 10

This is a Long Answer Type Questions as classified in NCERT Exemplar

Explanation- Since, B is along the x-axis, for a circular orbit the momenta of the two particles are in the y-z plane. Let P1 and P2 be the momentum of the electron and positron, respectively. Both traverse a circle of radius R of opposite sense. Let P1 make an angle? with the y-axis P2 must make the same angle.

The centres of the respective circles must be perpendicular to the momenta and at a distance R. Let the centre of the electron be at Ce and of the positron at Cp . The coordinates of Ce is

Ce= (0, -Rsin θ, Rcosθ )

Cp= (0, -Rsin θ, -32R-Rcosθ )

The circles of the two

...more

New answer posted

a year ago

0 Follower 13 Views

A
alok kumar singh

Contributor-Level 10

This is a Long Answer Type Questions as classified in NCERT Exemplar

Explanation- the thicker wire has a resistance R, then the other wire has a resistance @R as the wires are of the same material but different area

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 66k Colleges
  • 1.2k Exams
  • 705k Reviews
  • 1850k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.