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New answer posted
7 months agoContributor-Level 10
This is a multiple choice type question as classified in NCERT Exemplar
(a), (b)As we know L= r p where r is position vector and p is the linear momentum . the direction of L is perpendicular to both r and p by right hand rule.
For particle 1
I1=r1 mv is out of the plane of the paper and perpendicular to r1 and p . similarly I2=r2 m (-v) is into the plane of the paper and perpendicular to r2 and -p.
Hence total angular momentum
L= L1+L2= I1=r1 mv+ (r2 m (-v)
L= mvd1-mvd2 as d2>d1
So total angular momentum will be inwards so I = l = mv (d2-d1)⊗
L= mvd1-mvd2 as d2>d1
So total angular momentum will be inwards so I = l = mv (d2-d1)?
New answer posted
7 months agoContributor-Level 10
This is a multiple choice type question as classified in NCERT Exemplar
(a), (c) For general rotational motion where axis of rotation is not symmetric . angular momentum L and angular velocity w need not be parallel. For general translational motion momentum p=mv hence p and v are always parallel.
New answer posted
7 months agoContributor-Level 10
This is a multiple choice type question as classified in NCERT Exemplar
(a) As no external torque acts on the system, angular momentum should be conserved hence Iw=constant
Where I is moment of inertia of the system and w is the angular velocity of the system.
So I1w1= I2w2
Where w1 and w2 are angular velocities before and after jumping.
Iw=
w2=2w
New answer posted
7 months agoContributor-Level 10
This is a multiple choice type question as classified in NCERT Exemplar
(a) Density is given as ρ (x) = a (1+bx2)
Where a and b are constant and 0
Let b=0 ρ (x) = a= constant
Hence COM will be at x =0.5m
Putting b=0 ain above option only a gives this answer.
We should not check options by putting a=0 because for a=0
New answer posted
7 months agoContributor-Level 10
This is a multiple choice type question as classified in NCERT Exemplar
(c) First the centre of mass of the system was on the dotted line and was shifted towards Q from the centre. When mass is removed it will be on the same line but shifed away from the centre and below 3rd quadrant.

New answer posted
7 months agoContributor-Level 10
This is a multiple choice type question as classified in NCERT Exemplar
(b) When the small piece Q is removed and glued to the centre of the plate . the mass closer to the z axis . hence moment of inertia decreases.
New answer posted
7 months agoContributor-Level 10
This is a multiple choice type question as classified in NCERT Exemplar
(d) we know that angular acceleration , given w=constant
where w is the angular velocity of the disc
Hence angular acceleration is zero.
New answer posted
7 months agoContributor-Level 10
This is a multiple choice type question as classified in NCERT Exemplar
(b) The initial velocity is vi = vey and after reflecting from the wall the final velocity is vf= -vey. The trajectory is described as r= yey+aez.
hence the change in momentum is r .
New answer posted
7 months agoContributor-Level 10
This is a multiple choice type question as classified in NCERT Exemplar
(c) Centre of mass lies towards the part of system of higher mass. In the above diagram the lower part is heavier bigger mass is downward . So COM lies below diameter.
New answer posted
7 months agoContributor-Level 10
The NCERT Exemplar provides great study material for preparing for the exam. It can help immensely in scoring high in the class 11 Physics exam. It helps in strengthening the concepts and improving understanding of how to solve complex problems. However, it is advised that it should be practiced alongside the NCERT textbook. The students can first read the theory from the NCERT book and then study from the NCERT Exemplar to apply the theory in solving questions. The Exemplar is a great tool for practice and revision.
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