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New question posted
7 months agoNew question posted
7 months agoNew answer posted
8 months agoContributor-Level 10
4.32
(a) Let be the angle at which the projectile is fired w.r.t. the x-axis, since depends on t
Therefore tan since (Vy=Voy -gt and Vx = Vox)
(b) Since = sin2 /2g…….(1)
R = sin2 /g …….(2)
Dividing (1) by (2)
( /R) = [ sin2 /2g]/[ sin2 /g] = / 4
New answer posted
8 months agoContributor-Level 10
4.31

Speed of the cyclist = 27 km/h = 7.5 m/s
Radius of the road = 80m
The net acceleration is due to braking and the centripetal acceleration
Acceleration due to braking = 0.5 m/s2
Centripetal acceleration a = v2r = (7.5)2/80= 0.703 m/s2
The resultant acceleration is given by a = sqrt ( + ) = sqrt ( + ) = 0.86 m/s2
tan = AC / at = 0.7/0.5, = 54.5
New answer posted
8 months agoContributor-Level 10
4.30

Speed of the fighter plane = 720 km/h = 200 m/s
The altitude of the plane = 1.5 km =1500 m
Velocity of the shell = 600 m/s
= 200/600
Let H be the minimum altitude for the plane to fly, without being hit
Using equation H = sin2 (90-
= (6002cos2 )/2g
= 360000 { ( 1 + cos2 )/2}/2 10
= 16000 m = 16 km
New answer posted
8 months agoContributor-Level 10
4.29 The angle of projectile = 30
The bullet hits the ground at a distance of 3 km, Range R = 3 km
We know horizontal range for a projectile motion, R = sin2 / g
3 = sin60 / g
= 3/ sin60 = 3.464 …………… (1)
To hit a target at 5 km,
Max Range, = …………. (2)
On comparing equation (1) and (2), we get
= 3.464
Hence, the bullet will not hit the target even by adjusting its angle of projection.
New answer posted
8 months agoContributor-Level 10
4.28
(a) We cannot associate the length of a wire bent into a loop with a vector.
(b) We can associate a plane area with a vector.
(c) We cannot associate the volume of a sphere with a vector.
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