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4 months ago

Physics Physics Motion in Straight Line

A small toy starts moving from the position of rest under a constant acceleration. If it travels a distance of 10m in t s, the distance travelled by the toy in the next t s will be:

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Vishal Baghel

Contributor-Level 10

According to question, we can write

10 = $\frac{1}{2} a t^{2} . . . . . . . . . . . . . . . (1) a n d$

$10 + x = \frac{1}{2} a {(2 t)}^{2} . . . . . . . . . . . . . . . . (2)$

$\Rightarrow X = \frac{1}{2} A [{(2 t)}^{2} - t^{2}] = 3 (\frac{1}{2} a t^{2}) = 30 m$

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4 months ago

Physics Class 11th

What does zero elastic moduli mean?

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Aadit Singh Uppal

Contributor-Level 10

This is the case of fluids or gases. In such scenarios, the material does not have any limit to its flexibility and can be deformed to any extent. Such materials do not possess any stiffness and cannot regain their original form as they show no resistance towards any kind of pressure.

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4 months ago

Physics Class 11th

Which element is known to have the highest elastic moduli?

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Aadit Singh Uppal

Contributor-Level 10

A diamond crystal with young modulus of more than 1050 Gpa is known to be the element which has the highest elastic moduli found in nature. This is possible due to the high electron density as well as strong covalent bonds between the carbon atoms.

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4 months ago

Physics Physics Ncert Solutions Class 12th

A telegraph line of length 100km has a capacity of $0.01 μ F / k m$ and it carries an alternating current at 0.5 kilo cycle per second. If minimum impedance is required, then the value of the inductance that need to be introduced in series is _________mH.

(if p = $\sqrt[]{10}$ )

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Raj Pandey

Contributor-Level 9

C = 10^-6 f

f = 0.5 * 10³ = 500

$z = \sqrt[]{x_{R}^{2} + {(x_{L} - x_{C})}^{2}}$

for minimum impedance :

x_L = x_C

$\Rightarrow ω^{2} = \frac{1}{L C}$

$\Rightarrow L = \frac{1}{π^{2}} = \frac{1}{10} * 1000 = 100 m H$

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4 months ago

Physics Class 12th

(if p = $\sqrt[]{10}$ )

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New answer posted

4 months ago

Physics Physics Moving Charges and Magnetism

A singly ionized magnesium atom (A = 24) ion is accelerated to kinetic energy 5 ke V, and is projected perpendicularly into a magnetic field B of the magnitude 0.5 T. The radius of path formed will be ________cm.

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Raj Pandey

Contributor-Level 9

$r = \frac{m v}{q B} = \frac{\sqrt[]{2 k m}}{q B}$

$\frac{\sqrt[]{2 * 5 * 1 0^{3} * 1.6 * 1 0^{- 19} * 24 * 1.66 * 1 0^{- 27}}}{1.6 * 1 0^{- 19} * \frac{1}{2}}$

= 9.975 * 10^-2 cm

= 9.975 cm

$r \approx 10$ cm

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4 months ago

Physics Physics Thermodynamics

The total internal energy of two mole mono atomic ideal gas at temperature T = 300K will be __________J. (Given R = 8.31 J/mol.K)

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Raj Pandey

Contributor-Level 9

$U = n c_{v} T$

$\begin{array}{l} = 2 * \frac{3}{2} * R * 300 \\ = 7479 J \end{array}$

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4 months ago

Physics Class 11th

A hanging mass M is connected to a four times bigger mass by using a string-pulley arrangement, as shown in the figure. The bigger mass is placed on a horizontal ice-slab and being pulled by 2 Mg force. In this situation, tension in the string is $\frac{x}{5} M g$ for x_________. Neglect mass of the string and fiction of the block (bigger mass) with ice slab.

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Raj Pandey

Contributor-Level 9

Using newton's law:

2mg – T = 4ma - (1)

T – mg = ma - (2)

From (1) & (2) :

$m g = 5 m a \Rightarrow a = \frac{g}{5} = 2 m / s^{2}$

$T = m g + \frac{m g}{5} = \frac{6 m g}{5}$

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4 months ago

Physics Class 11th

A man of 60kg is running on the road and suddenly jumps into stationary trolly car of mass 120kg. Then, the trolly car starts moving with velocity 2ms^-¹. The velocity of the running man was _________ ms^-¹, when he jumps into the car:

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Raj Pandey

Contributor-Level 9

Using conservation of momentum:

60 * v = (60 + 120) * 2

⇒v = 6m/s

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4 months ago

Physics Class 11th

The position vector of 1kg object is $\vec{r} = (3 \hat{i} - \hat{j}) m$ and its velocity $\vec{v} = (3 \hat{j} + \hat{k}) m s^{- 1} .$ The magnitude of is angular momentum is $\sqrt[]{x} N m$ where x is________.

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Raj Pandey

Contributor-Level 9

$\overset{?}{L} = \overset{?}{r} * m \overset{?}{v}$

= $(3 \hat{i} ? \hat{j}) * (3 \hat{j} + \hat{k})$

$= 9 \hat{k} + 3 (? \hat{j}) ? \hat{i}$

$= ? \hat{i} ? 3 \hat{j} + 9 \hat{k}$

$| \overset{?}{L} | = \sqrt[]{1 + 9 + 81} = \sqrt[]{91}$

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