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New answer posted

2 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

According to question, we can write

R = u 2 s i n 2 θ g u 2 = g R m a x , w h e r e θ = 4 5 °

H m a x = u 2 2 g = g R m a x 2 g = R m a x 2 = 1 0 0 2 = 5 0 m

New answer posted

2 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

Pressure * time = F t A = [ M L T 2 ] [ T ] [ L 2 ] = [ M L 1 T 1 ]  

 Coefficient of viscosity, η = [ M L 1 T 1 ]  

  F v i s c o u s = η A Δ v Δ y  

New answer posted

2 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

According to question, we can write

2 V 2 + 2 r = V 2 + r 2

2 + 2 r = 4 + r r = 2 Ω  

New answer posted

2 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

According to relation between field and potential, we can write

E = d V d x ( i ^ ) = d ( 3 x 2 ) d x ( i ^ ) = 6 x ( i ^ )

E ( 1 , 0 , 3 ) = 6 ( i ^ ) N / C

New answer posted

2 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

According to Newton's law of motion, we can write

ma = mg – N = mg -  m g 4 = 3 m g 4                              

a = 3 g 4

 

New answer posted

2 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

According to conservation of energy, we can write

Gain in kinetic energy = Loss in potential energy

 Kf – Kin = Uin - Uf

K - = mgy – mg (y – y0) = mgy0

New answer posted

2 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

According to Newton's laws of motion, we can write

4a = 4g – T . (1), and

40a = T - fk = T μ - (40g) ……………… (2)

Adding equations (1) and (2), we can write

44a = 40 – 0.02 * (400) = 32

a = 3 2 4 4 = 8 1 1 m / s 2

 

New answer posted

2 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

According to Lorentz's Force, we can write

F = F E l e c t r i c + F M a g n e t i c = q E + q ( v * B ) , s o  

Statement I is correct but Statement II is incorrect

New answer posted

2 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

 According to question, we can write

Total moles of gas = n = nOxygen + nOxygen = 1 6 2 + 1 2 8 3 2 = 1 2 m o l e s  

Volume of gas = 12 * 22.4 litre = 268.8 litre = 2.688 * 105 cm3 ? 2 7 * 1 0 4 c m 3  

New answer posted

2 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

According to question, we can write

ω = π = g l l = g π 2 = 9 . 8 ( 3 . 1 4 ) 2 = 0 . 9 9 3 9 5 = 9 9 . 4 c m

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