Physics

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New answer posted

a year ago

0 Follower 57 Views

V
Vishal Baghel

Contributor-Level 10

v = ω k = 5 π * 3 0 π = 1 5 0 = T 1 1 0 0

⇒ T = 2 2 5 0 0 0 0 1 0 0 = 2 2 5 N

New answer posted

a year ago

0 Follower 24 Views

V
Vishal Baghel

Contributor-Level 10

λ 1 w = 3 * 5 4 0 2 w

λ 1 = 8 1 0 n m

New answer posted

a year ago

0 Follower 22 Views

V
Vishal Baghel

Contributor-Level 10

i m a x = P m a x V z = 3 1 0 0

∴ R s m i n = V R S i m a x

= 3 3 / 1 0 0 = 1 0 0 Ω

New answer posted

a year ago

0 Follower 27 Views

V
Vishal Baghel

Contributor-Level 10

Q ( i ) = ( M B r − M K r ) c 2 > 0

Q ( i i ) = ( M B r − M S e − 2 M e ) c 2 > 0 Q ( i i ) = ( M B r − M s e ) c 2 > 0

New answer posted

a year ago

0 Follower 9 Views

V
Vishal Baghel

Contributor-Level 10

This experiment is the famous Davission-Germer experiment which establishes wave nature of electrons.

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

Low pass filter will allow low frequency signal to pass while high pass filter allow high frequency to pass through

New answer posted

a year ago

0 Follower 99 Views

V
Vishal Baghel

Contributor-Level 10

Heat will develop due to eddy current which will oppose the motion and hence a force is required.

New answer posted

a year ago

0 Follower 74 Views

V
Vishal Baghel

Contributor-Level 10

Apply Ampere's Law

For inside

B 2 π r = μ 0 J π r 2            

⇒ B ∝ r      

For outside

B 2 π r = μ 0 J π R 2

⇒ B ∝ 1 r       

New answer posted

a year ago

0 Follower 271 Views

V
Vishal Baghel

Contributor-Level 10

W D = Δ Q V

⇒ Δ Q = 4 μ C

Q i = 2 * 4 2 + 4 * 6 = 8 μ C

Q f = 1 2 μ C = C e q * 6

C e q = 2 μ F ⇒ C 1 = C 2 = 4 μ F

k = C 1 C 0 = 2

New answer posted

a year ago

0 Follower 63 Views

V
Vishal Baghel

Contributor-Level 10

i = v R + G

i 2 = v S G S + G + R * S S + G

⇒ 2 S S G + R G + R S = 1 R + G

S R R − S = G

R > > S

⇒ G ≈ S

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