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9 months ago

Physics Motion in a Plane

An electron in a research apparatus follows a circle path. On the electron's first circuit of the apparatus, its speed is v₀ and the radius of its circular path is R. Each time it makes on circuit, it passes a short region where it receives a “kick” and gains an additional speed of $\frac{v_{0}}{100} .$ The electron follows a circular path such that the magnitude of its acceleration is always the same. What is the radius of the circular path after the electron has received 10 kicks?

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Vishal Baghel

Contributor-Level 10

$a = \frac{v_{0}^{2}}{R}$ $\frac{_{}^{}}{}$

after 10 kicks, $v = v_{0} + \frac{10 v_{0}}{100} = 1.1 v_{0}$ $_{} \frac{_{}}{}_{}$

$\Rightarrow R_{1} = 1.21 R$

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New answer posted

9 months ago

Physics Class 11th

A projectile travels at θ below horizontal 1 sec after projection as shown. What is the value of θ?

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Vishal Baghel

Contributor-Level 10

$t a n θ = \frac{v_{y}}{v_{x}} = \frac{u_{y} - g t}{u_{x}}$

$\Rightarrow t a n θ = | \frac{8 - 10}{4} | = | - \frac{1}{2} |$

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9 months ago

Physics Units and Measurement

Which of the following is a CORRECT statement?

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Vishal Baghel

Contributor-Level 10

(1) 2.3056 -> 4 decimals

10.138 -> 3 decimals

-7.4671 -> 4 decimals

_________________

4.9765

Answer should have 3 decimals.

(2) 2.38 * 1.0 = 2.38 -> answer should have 2 significant digits

(3) $\frac{8.05}{3.1} = 2.59 \approx 2.6$ answer should have 2SD

(4) 1.11 - 0.1 = 1.01 $\approx$ 1.0 but is an intermediate step so we keep 1 digit extra. 1.01 * 9.0 = 9.09 $\approx$ 9.1 -> both 1.01 and 9.0 have 2SD

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New answer posted

9 months ago

Physics Waves

A source of sound S is moving with a velocity of 50 m/s towards a stationary observer. The observer measures the frequency of the source as 1000 Hz. What will be the apparent frequency (in Hz) of the source when it is moving away from the observer after crossing him? (Take speed of sound in air as 350 m/s)

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Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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New answer posted

9 months ago

Physics Mechanical Properties of Fluids

Force required to separate two glass plates of area 100cm² with a thin film of water 0.05 cm thick between them is____. (in N). (Surface tension of water is 70x10^-3N / m , consider complete wetting)

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Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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New answer posted

9 months ago

Physics Physics Ray Optics and Optical Instruments

A lens is placed between a source of light and screen. It forms real image on screen for two different positions. If height of one image is 20 cm and the other is 80 cm, then the height of source of light (in cm) is_____.

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Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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New answer posted

9 months ago

Physics Class 11th

The position vector of 1kg object is $\vec{r} = (3 \hat{i} - \hat{j}) m$ and its velocity $\vec{v} = (3 \hat{j} + \hat{k}) m s^{- 1} .$ The magnitude of is angular momentum is $\sqrt[]{x} N m$ where x is________.

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Vishal Baghel

Contributor-Level 10

$\vec{L} = \vec{r} * m \vec{v}$

= $(3 \hat{i} - \hat{j}) * (3 \hat{j} + \hat{k})$

$= 9 \hat{k} + 3 (- \hat{j}) - \hat{i}$

$= - \hat{i} - 3 \hat{j} + 9 \hat{k}$

$| \vec{L} | = \sqrt[]{1 + 9 + 81} = \sqrt[]{91}$

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9 months ago

Physics Mechanical Properties of Fluids

The velocity of a small ball of mass 0.3g and density 8 g/cc when dropped in a container filled with glycerine becomes constant after some time. If the density of glycerine is 1.3 g/cc, then the value of viscous force acting on the ball will be x * 10^-4 N, value of x is________. [use g = 10 m/s²]

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Vishal Baghel

Contributor-Level 10

m = 0.3g density, $ρ_{(b a l l)} = 8 g / c c$ $∴ V = \frac{m}{ρ} = \frac{0.3}{8} c c$

$ρ_{g l y c e r e n e} = 1.3 g / c c = 1.3 * 1 0^{3} k g / m^{3}$

F_v + F_B = mg.

Þ F_v = mg – F_B = .3 * 10^-3 * 10 – 1.3 * $\frac{0.3}{8} * 1 0^{- 6} * 10 * 1 0^{3}$

$= 3 * 1 0^{- 3} - \frac{. 39}{8} * 1 0^{- 2} = 3 * 1 0^{- 3} - . 5 * 1 0^{- 3}$

= 2.5 * 10^-3N

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9 months ago

Physics Physics Wave Optics

In a Young's double slit experiment, an angular width of the fringe is 0.53° on a screen place at 2m away for particular wavelength of 450 nm. The angular width of the fringe, when whole system is immersed in a medium of refractive index 7/5, is $\frac{1}{α} .$ The value of a is__________.

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Vishal Baghel

Contributor-Level 10

we know, = $\frac{λ}{d}$ $\frac{}{}$ $μ = \frac{C}{V} = \frac{C}{υ λ}$ $\frac{}{} \frac{}{}$

$_{} \frac{}{_{}_{}}$ $λ_{1} = \frac{C}{μ_{1} υ_{1}}$ [with change in medium frequency remain constant]

$λ_{2} = \frac{C}{μ_{2} υ_{2}}$

$\frac{λ_{2}}{λ_{1}} = \frac{μ_{1}}{μ_{2}} = \frac{5}{7}$ $λ_{2} = \frac{5}{7} λ_{1}$

$θ_{1} = \frac{λ_{1}}{d_{1}}$

2= $\frac{λ_{2}}{d_{2}}$

$\frac{θ_{2}}{θ_{1}} = \frac{λ_{2}}{λ_{1}} [? d_{1} = d_{2}]$

2 $= \frac{5}{7} * θ_{1}$

$θ_{2} = \frac{5}{7} * 0.35$

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New answer posted

9 months ago

Physics Electromagnetic Waves

The intensity of the light from a bulb incident on a surface is 0.22 W/m². The amplitude of the magnetic field in this light – wave is__________ * 10^-9 T.

(Given : Permittivity of vacuum $\in_{0} = 8.85 * 1 0^{- 12} C^{2} N^{- 1} - m^{- 2},$ speed of light in vacuum c = 3 * 10⁸ ms^-1)

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Vishal Baghel

Contributor-Level 10

$\frac{B_{0}^{2}}{2 μ_{0}} C$

$B_{0}^{2} = \frac{I 2 μ_{0}}{C}$

$B_{0}^{2} = \frac{0.22 * 2 * 4 * 1 0^{- 7}}{9 * 108}$

B₀ = 42.9 * 10^-9

42.9 Ans

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